Environmental Engineering Reference
In-Depth Information
fore, in applications, we can directly write out the solutions of the 189 PDS based
on Eqs. (6.123) and (6.139) without going through the individual details.
Remark 2
.If
β
mnk
is purely imaginary for some
m
,
n
and
k
such that
β
mnk
=
e
iβ
mnk
t
e
−
iβ
mnk
t
2i
−
i
γ
mnk
(
γ
mnk
is real
)
, we can change sin
β
mnk
t
into
by using the for-
e
i
z
e
−
i
z
−
mula sin
z
=
for any imaginary variable
z
. We thus have the term
2i
1
β
mnk
1
1
γ
mnk
s
h
e
γ
mnk
t
e
−
γ
mnk
t
sin
β
mnk
t
=
γ
mnk
(
−
)=
γ
mnk
t
.
2
6.7 Mixed Problems in a Spherical Domain
Boundary conditions of all the three kinds for mixed problems in a spherical domain
are separable with respect to the spatial variables in a spherical coordinate system. In
this section we apply the separation of variables to find solutions of mixed problems
in a spherical coordinate system
⎧
⎨
u
t
τ
0
+
B
2
∂
∂
A
2
u
tt
=
Δ
u
(
r
,
θ
,
ϕ
,
t
)+
t
Δ
u
(
r
,
θ
,
ϕ
,
t
)
+
f
(
r
,
θ
,
ϕ
,
t
)
,
0
<
r
<
a
,
0
<
θ
<
π
,
0
<
ϕ
<
2
π
,
0
<
t
,
⎩
L
(
u
,
u
r
)
|
r
=
a
=
0
,
u
(
r
,
θ
,
ϕ
,
0
)=
Φ
(
r
,
θ
,
ϕ
)
,
u
t
(
r
,
θ
,
ϕ
,
0
)=
ψ
(
r
,
θ
,
ϕ
)
,
(6.140)
where
Ω
stands for a sphere of radius
a
, with
∂Ω
as its boundary. The boundary
condition
L
(
u
,
u
r
)
|
r
=
a
=
0 contains all three kinds. We will also examine the relation
among solutions from
Φ
(
r
,
θ
,
ϕ
)
,
ψ
(
r
,
θ
,
ϕ
)
and
f
(
r
,
θ
,
ϕ
,
t
)
, respectively.
6.7.1 Solution from
ψ
(
r
,
θ
,
ϕ
)
The solution due to
ψ
(
r
,
θ
,
ϕ
)
satisfies
⎧
⎨
u
t
τ
0
+
B
2
∂
∂
A
2
u
tt
=
Δ
u
(
r
,
θ
,
ϕ
,
t
)+
t
Δ
u
(
r
,
θ
,
ϕ
,
t
)
,
0
<
r
<
a
,
0
<
θ
<
π
,
0
≤
ϕ
≤
2
π
,
0
<
t
,
(6.141)
⎩
L
(
u
,
u
r
)
|
r
=
a
=
0
,
u
(
r
,
θ
,
ϕ
,
0
)=
0
,
u
t
(
r
,
θ
,
ϕ
,
0
)=
ψ
(
r
,
θ
,
ϕ
)
.
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