Environmental Engineering Reference
In-Depth Information
fore, in applications, we can directly write out the solutions of the 189 PDS based
on Eqs. (6.123) and (6.139) without going through the individual details.
Remark 2 .If
β mnk is purely imaginary for some m , n and k such that
β mnk =
e mnk t
e mnk t
2i
i
γ mnk ( γ mnk is real
)
, we can change sin
β mnk t into
by using the for-
e i z
e i z
mula sin z
=
for any imaginary variable z . We thus have the term
2i
1
β mnk
1
1
γ mnk s h
e γ mnk t
e γ mnk t
sin
β mnk t
=
γ mnk (
)=
γ mnk t
.
2
6.7 Mixed Problems in a Spherical Domain
Boundary conditions of all the three kinds for mixed problems in a spherical domain
are separable with respect to the spatial variables in a spherical coordinate system. In
this section we apply the separation of variables to find solutions of mixed problems
in a spherical coordinate system
u t
τ 0 +
B 2
A 2
u tt =
Δ
u
(
r
, θ , ϕ ,
t
)+
t Δ
u
(
r
, θ , ϕ ,
t
)
+
f
(
r
, θ , ϕ ,
t
) ,
0
<
r
<
a
,
0
< θ < π ,
0
< ϕ <
2
π ,
0
<
t
,
L
(
u
,
u r ) | r = a =
0
,
u
(
r
, θ , ϕ ,
0
)= Φ (
r
, θ , ϕ ) ,
u t (
r
, θ , ϕ ,
0
)= ψ (
r
, θ , ϕ ) ,
(6.140)
where
Ω
stands for a sphere of radius a , with
∂Ω
as its boundary. The boundary
condition L
(
u
,
u r ) | r = a =
0 contains all three kinds. We will also examine the relation
among solutions from
Φ (
r
, θ , ϕ )
,
ψ (
r
, θ , ϕ )
and f
(
r
, θ , ϕ ,
t
)
, respectively.
6.7.1 Solution from
ψ (
r
, θ , ϕ )
The solution due to
ψ (
r
, θ , ϕ )
satisfies
u t
τ 0 +
B 2
A 2
u tt =
Δ
u
(
r
, θ , ϕ ,
t
)+
t Δ
u
(
r
, θ , ϕ ,
t
) ,
0
<
r
<
a
,
0
< θ < π ,
0
ϕ
2
π ,
0
<
t
,
(6.141)
L
(
u
,
u r ) | r = a =
0
,
u
(
r
, θ , ϕ ,
0
)=
0
,
u t (
r
, θ , ϕ ,
0
)= ψ (
r
, θ , ϕ ) .
 
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