Environmental Engineering Reference
In-Depth Information
br I 1 b
r 2
At
(
)
2
At
1
2 A
r
r )
d r +
¯
2 At ¯
=
(
ψ (
ψ (
At
)
At
)
2
r 2
At
bI 1 b (
r 2
At
At
)
2
1
M )
d r
=
ψ (
d S
8
π
A
r 2
(
At
)
2
At
S M
r
1
M )
+
ψ (
d S
4
π
A 2 t
S r
bI 1 b (
r 2
At
At
)
2
1
1
2
M )
d r
=
ψ (
d S
4
π
A
2
r 2
(
At
)
At
S r
1
At
.
M )
+
ψ (
d S
S r
Thus the solution of
u t
τ 0 +
A 2
R 3
u tt
=
Δ
u
,
× (
0
, + ) ,
(5.119)
u
(
M
,
0
)=
0
,
u t (
M
,
0
)= ψ (
M
)
is
1
1
At
t
0
A e
M )
u
(
M
,
t
)=
W ψ (
M
,
t
)=
ψ (
d S
4
π
S At
(5.120)
.
bI 1 b (
r 2
At
At
)
2
1
2
M )
d r
+
ψ (
d S
r 2
(
At
)
2
At
S M
r
Finally, the solution of PDS (5.115) comes from the solution structure theorem,
1
W ϕ (
t
τ 0 +
u
(
M
,
t
)=
M
,
t
)+
W ψ (
M
,
t
)+
W f τ (
M
,
t
τ )
d
τ ,
(5.121)
t
0
where f τ =
f
(
M
, τ )
.
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