Environmental Engineering Reference
In-Depth Information
The solution of PDS (3.39) follows directly from the solution structure theorem as
t
u
=
W f τ (
x
,
t
τ )
d
τ
0
V
d
t
+
2 a 2
τ )+ ξ
(
t
τ )
h
=
d
τ
f
( ξ , τ )
(
x
, ξ ,
t
h V
(
x
,− ξ ,
t
τ )
ξ .
2 a 2
ξ +
(
t
τ )
0
0
(3.40)
Remark 3. Solutions of PDS (3.37) and (3.39) that are subjected to boundary con-
dition of the second kind can be obtained by letting h
=
0 in Eqs. (3.38) and (3.40).
3.4.4 PDS with Variable Thermal Conductivity
, the task of seeking PDS
solutions of heat-conduction equations becomes difficult. There exists no well-
developed method for developing analytical solutions. Numerical method are nor-
mally appealed for numerical solutions. Here we detail the procedure of developing
analytic solutions of heat-conduction equations with variable thermal conductivity
of type k
When thermal conductivity is variable so that k
=
k
(
x
,
t
)
=
k
(
x
)
by using the example
cu t =
ρ
x [
k
(
x
)
u x ] , (
0
,
l
) × (
0
, + ) ,
(3.41)
u
(
0
,
t
)=
u
(
l
,
t
)=
0
,
u
(
x
,
0
)=
f
(
x
) ,
where
and c are the density and the specific heat of the material. The thermal
conductivity k
ρ
(
x
) >
0 is a differentiable function of x .
Transform into an Eigenvalue Problem of an Integral Equation
Consider a solution of type u
(
x
,
t
)=
X
(
x
)
T
(
t
)
. Substitute it into the equation of
PDS (3.41) to obtain eigenvalue problems
d
d x [
k
(
x
)
X x ]+ λ
X
=
0
,
X
(
0
)=
X
(
l
)=
0
(3.42)
and
T t + λ
ρ
c T
=
0
.
(3.43)
Here
λ
is the separation constant.
 
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