Environmental Engineering Reference
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a 2
u t
=
Δ
u
+
f
(
M
,
t
) ,
Ω × (
0
, + ) ,
L u
∂Ω =
,
u
(3.2)
0
,
n
(
,
)=
,
u
M
0
0
a 2
=
+
(
,
) ,
Ω × (
, + ) ,
u t
Δ
u
f
M
t
0
∂Ω =
L u
,
u
(3.3)
0
,
n
(
,
)= ϕ (
) ,
u
M
0
M
(
,
)
(
,
,
)
where M represents the point x ,
x
y
and
x
y
z
in one-, two- and three-dimensional
space. For the one-dimensional case,
Δ
u is defined as u xx .
Theorem. Suppose that u 1 =
W ϕ (
M
,
t
)
is the solution of (3.1), then
t
1. u 2 =
W f τ (
M
,
t
τ )
d
τ
is the solution of (3.2), where f τ =
f
(
M
, τ )
;
0
t
2. u 3 =
W ϕ (
M
,
t
)+
W f τ (
M
,
t
τ )
d
τ
is the solution of (3.3).
0
Proof.
1. Since W f τ (
M
,
t
τ )
satisfies
W f τ
a 2
t =
Δ
W f τ ,
Ω × (
0
, + ) ,
∂Ω =
L W f τ ,
W f τ
0
,
n
W f τ t = τ =
f
(
M
, τ ) ,
then
t
t
2 u 2
u 2 =
a 2
a 2
t 2
Δ
W f τ (
M
,
t
τ )
d
τ
Δ
W f τ (
M
,
t
τ )
d
τ
t
0
0
t
a 2 t
W f τ τ = t
W f τ
=
d
τ +
0 Δ
W f τ d
τ
t
0
d
t
W f τ
a 2
=
τ +
(
,
)=
(
,
) .
Δ
W f τ
f
M
t
f
M
t
t
0
Therefore, u 2 satisfies the equation of (3.2).
Also,
L u 2
∂Ω =
L W f τ ,
∂Ω
t
,
u 2
W f τ
τ =
d
0
n
n
0
 
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