Agriculture Reference
In-Depth Information
Table 9.3
r s ” contingency table
B
A
A
B
B
...
B j
...
B s
Total
1
2
(
A
B
1 )
(
A
B
2 )
(
A
B j )
(
A
B s )
(
A
1 )
1
1
1
1
1
A
(
A
B
1 )
(
A
B
2 )
(
A
B j )
(
A
B s )
(
A
2 )
2
2
2
2
2
...
A i
( A i B 1 )
( A i B 2 )
( A i B j )
( A i B s )
( A i )
...
A r
(
A r B
1 )
(
A r B
2 )
(
A r B j )
(
A r B s )
(
A r )
Total
(
B
1 )
(
B
2 )
(
B j )
(
B s )
N
s
B s ). The various cell
frequencies are expressed according to the
following table format known as “
classes (
B 1 ,
B 2 ,
...
,
both the
attributes
A i
and
B j
with
P 1 ðA i Þ¼ P 1 ðB j Þ¼N
, where
N
is
r s
the total frequency.
1. Table 9.3
The problem is to test if the two
attributes A and B under consideration
are independent or not. Under the null
hypothesis
manifold contingency table where (
A i )is
the frequency of the individual units
possessing the attribute
A i ,(
i ¼
1, 2, 3,
...
B j ) is the frequency of the individ-
ual units possessing the attribute
r
,
), (
B j
H 0 : The attributes are inde-
pendent, the theoretical cell frequen-
cies are calculated as follows:
(
A i B j ) is the fre-
quency of the individual units possessing
j ¼
1, 2, 3,
...
,
s
), and (
A i ¼ ðA i Þ
N
PA½¼
probability that an individual unit possesses the attribute
; i ¼
1
;
2
; ...; r;
PB j ¼
B j ¼ ðB j Þ
N
; j ¼
;
; ...; s:
probability that an individual unit possesses the attribute
1
2
Since the attributes A i and B j are inde-
pendent, under null hypothesis, using
the theorem of compound probability
(Chap. 6 ), we get
¼
PA i B j
probability that an individual unit possesses both the attributes
A i and
B j
¼ PA½PB j ¼ ðA i Þ
N
ðB j Þ
N
; i ¼
1
;
2
;
3
; ...; r; j ¼
1
;
2
;
3
; ...; s
and
e ¼
A i B j
expected number of individual units possessing both the attributes
A i and
B j
¼ ðA i ÞðB j Þ
N
¼ N: PA i B j
e ¼ ðA i ÞðB j Þ
A i B j
;
ð
i ¼
1
;
2
;
3
; ...; r; j ¼
1
;
2
;
3
; ...; s
Þ
N
By using this formula, we can find out
the expected frequencies for each of
the cell frequencies (
the null hypothesis of independence
of attributes. The approximate test
statistic for the test of independence
of attributes
A i B j )(
i ¼
1, 2,
3,
...
,
r
;
j ¼
1, 2, 3,
...
..,
s
), under
is derived from the
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