Environmental Engineering Reference
In-Depth Information
Example 15.3
NPV
and sensitivity analysis to major investment parameters
Taking the same data as presented in Example 15.2, assuming in addition an inter-
est rate of 6%, calculate both the
NPV
and the sensitivities of changes of the initial
investment (
I
0
),
CF
, expected lifetime of the installation (
n
), and interest rate (
i
).
Solution
As the
CF
pattern is constant, Equation (15.11) holds
n
10
I
0
+
CF
1+
i
ð
Þ
−
1
ð
1+0
6
Þ
−
1
:
NPV
i
%
=
−
n
=
−
20 M
€
+2
:
5M
€
10
=
−
1
:
6M
€
i
1+
i
ð
Þ
0
06 1 + 0
ð
06
Þ
:
:
The sensitivity of
NPV
i
%
with respect
to
I
0
can be found by simple
differentiation:
∂
NPV
i
%
∂
I
0
=
−
1
Regarding the sensitivity to
CF
,
n
10
∂
NPV
i
%
∂
ð
1+
i
Þ
−
1
ð
1+0
06
Þ
−
1
:
=
n
=
10
=+7
4
:
CF
i
1+
i
ð
Þ
0
:
06 1 + 0
ð
:
06
Þ
With respect to the expected lifetime, and therefore depreciation time considered
(
n
), the sensitivity is
∂
NPV
i
%
∂
=
CF
ln 1 +
i
ð
Þ
ln 1 + 0
ð
06
Þ
:
n
=2
5M
10
=1
4M
:
€
:
€
n
i
1+
i
ð
Þ
0
:
06 1 + 0
ð
:
06
Þ
Finally, with respect to the interest rate, the sensitivity is
n
+1
+1
10 + 1
+1
∂
NPV
i
%
∂
i
=
CF
in
+1
ð
Þ−
ð
1+
i
Þ
0
:
06 10 + 1
ð
Þ−
ð
1+0
:
06
Þ
=2
5M
:
€
n
+1
06
2
1+0
10 + 1
i
2
1+
i
ð
Þ
0
ð
:
06
Þ
:
=
−
87
1M
:
€
This example shows that the time value of money matters; whereas a
POT
anal-
ysis shows payback time of 8 years, the
NPV
is
—
given the interest rate of 6%
—
still negative!
A way to estimate the investment costs of process equipment is illustrated in the cal-
culation sheet presented in Table 15.3 with an explanation of terms in Table 15.4.
Once the investment cost is known for a certain process equipment (
I
equipment
) with
a capacity
A
(e.g., expressed in terms of mass flow, volumetric flow, or power unit),
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