Environmental Engineering Reference
In-Depth Information
Example 15.3
NPV and sensitivity analysis to major investment parameters
Taking the same data as presented in Example 15.2, assuming in addition an inter-
est rate of 6%, calculate both the NPV and the sensitivities of changes of the initial
investment ( I 0 ), CF , expected lifetime of the installation ( n ), and interest rate ( i ).
Solution
As the CF pattern is constant, Equation (15.11) holds
n
10
I 0 + CF 1+ i
ð
Þ
1
ð
1+0
6
Þ
1
:
NPV i % =
n =
20 M
+2
:
5M
10 =
1
:
6M
i 1+ i
ð
Þ
0
06 1 + 0
ð
06
Þ
:
:
The sensitivity of NPV i % with respect
to I 0 can be found by simple
differentiation:
NPV i %
I 0
=
1
Regarding the sensitivity to CF ,
n
10
NPV i %
ð
1+ i
Þ
1
ð
1+0
06
Þ
1
:
=
n =
10 =+7
4
:
CF
i 1+ i
ð
Þ
0
:
06 1 + 0
ð
:
06
Þ
With respect to the expected lifetime, and therefore depreciation time considered
( n ), the sensitivity is
NPV i %
= CF ln 1 + i
ð
Þ
ln 1 + 0
ð
06
Þ
:
n =2
5M
10 =1
4M
:
:
n
i 1+ i
ð
Þ
0
:
06 1 + 0
ð
:
06
Þ
Finally, with respect to the interest rate, the sensitivity is
n +1 +1
10 + 1 +1
NPV i %
i
= CF in +1
ð
Þ−
ð
1+ i
Þ
0
:
06 10 + 1
ð
Þ−
ð
1+0
:
06
Þ
=2
5M
:
n +1
06 2 1+0
10 + 1
i 2 1+ i
ð
Þ
0
ð
:
06
Þ
:
=
87
1M
:
This example shows that the time value of money matters; whereas a POT anal-
ysis shows payback time of 8 years, the NPV is
given the interest rate of 6%
still negative!
A way to estimate the investment costs of process equipment is illustrated in the cal-
culation sheet presented in Table 15.3 with an explanation of terms in Table 15.4.
Once the investment cost is known for a certain process equipment ( I equipment ) with
a capacity A (e.g., expressed in terms of mass flow, volumetric flow, or power unit),
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