Environmental Engineering Reference
In-Depth Information
The enthalpy introduced by the flow to a slice of the reactor is
X
+ X
φ n , i
φ n , i H i T re ðÞ
c p , i T
ð
T ref
Þ
ð
Eq
:
6
:
31
Þ
The enthalpy that leaves the slice is
X
+ X
φ n , i
φ n , i H i T re ðÞ
c p , i T+dT
ð
T ref
Þ
ð
Eq
:
6
:
32
Þ
The enthalpy generated in the slice due to the reaction of component A is
dV
ð
Δ r H
Þ −
ð
R A X A ,T
ð Þ
Þ
ð
Eq
:
6
:
33
Þ
If the reactor operates in steady state, there is no accumulation of heat in the slice.
The energy balance then reads
Rate of accumulation = rate of supply
rate of release + rate of production
+ heating
=
cooling
)
0= X
+ X
X
φ n , i
φ n , i H i T re ðÞ
c p , i T
ð
T ref
Þ−
φ n , i H i T re ðÞ
+dV
+ X
+d Q
φ n , i c p , i T+dT
ð
T ref
Þ
Δ r H
Þ −
ð
R A X A ,T
ð Þ
Þ
ð
Eq
:
6
:
34
Þ
This balance neglects any shaft work introduced to the system, for instance, the work
done by the turbine that pumps the flow. Simplifying the balance, we obtain
X
+d Q
φ n , i
c p , i dT = dV
ð
Δ r H
Þ − R A X A ,T
ð
ð Þ
Þ
ð
Eq
:
6
:
35
Þ
Dividing by dV and rearranging gives
+ d Q
dV
dV = Δ r H
ð
Þ −
ð
R A X A ,T
ð Þ
Þ
dT
X
ð
Eq
:
6
:
36
Þ
φ n , i
c p , i
Q = hA T f
The heat removed from the system by the coolant,
ð Þ
T
, can be expressed as
d Q = h T f
=
:
:
ð Þ
T
d A = h 4
ðÞ
d
ð Þ
T f
T
dV
ð
Eq
6
37
Þ
where d is the reactor diameter, h is the heat transfer coefficient, and T f is the temper-
ature of the coolant. Substituting the expression for d Q in Equation (6.36), we obtain
the final expression for the temperature gradient inside the reactor:
dT
dV =
ð
Δ r H
Þ −
ð
R A X A ,T
ð Þ
Þ
+ h 4
ðÞ
=
d
ð Þ
T f
T
X
ð
Eq
:
6
:
38
Þ
φ n , i c p , i
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