Biology Reference
In-Depth Information
¼
H
þ
½
HA
3
A
4
ðA1:3Þ
K
4
2
K
3
K
4
A
4
¼
H
þ
¼
H
þ
½
½
H
2
A
2
HA
3
ðA1:4Þ
K
3
3
K
2
K
3
K
4
A
4
H
þ
¼
H
þ
½
½
H
3
A
H
2
A
2
½
¼
ðA1:5Þ
K
2
4
H
þ
H
þ
½
½
H
3
A
A
4
½
H
4
A
¼
½
¼
ðA1:6Þ
K
1
K
1
K
2
K
3
K
4
By using these four relations, the expression for the total concentration can be
written in terms of [A
4
]:
4
3
2
H
þ
þ
H
þ
þ
H
þ
þ
H
þ
þ
½
½
½
½
A
4
A
4
A
4
A
4
A
4
C
0
¼
K
1
K
2
K
3
K
4
K
2
K
3
K
4
K
3
K
4
K
4
ðA1:7Þ
Dividing through by [A
4
] leads to
4
K
1
K
2
K
3
K
4
þ
3
K
2
K
3
K
4
þ
2
K
3
K
4
þ
H
þ
H
þ
H
þ
H
½
K
4
þ
C
0
A
4
1
a
4
¼
½
½
½
¼
ðA1:8Þ
1
Writing the right side of
Eq. (A1.8)
as a fraction with a common denominator and
then inverting the fraction gives the desired final expression
K
1
K
2
K
3
K
4
a
4
¼
K
1
K
2
K
3
þ K
1
K
2
K
3
K
4
:
ðA1:9Þ
4
3
2
H
þ
H
þ
H
þ
H
þ
½
þ
½
K
1
þ
½
K
1
K
2
þ
½
An important feature of
Eq. (A1.9)
to notice is that each term in the expression
actually represents the contribution of a particular protonated form, thus:
A
4
K
1
K
2
K
3
K
4
,
H
þ
HA
3
½
K
1
K
2
K
3
,
2
H
þ
H
2
A
2
½
K
1
K
2
,
3
H
þ
H
3
A
½
K
1
,
4
H
þ
H
4
A
This insight makes it easy to write the fraction of the polybasic acid that is in a
particular form: the term representing the particular protonated form appears in
the numerator, while the denominator is simply the sum of all the possible terms.
For example, the fraction existing as HA
3
is
½
,
H
þ
½
K
1
K
2
K
3
a
3
¼
K
1
K
2
K
3
þ K
1
K
2
K
3
K
4
;
ðA1:10Þ
4
3
2
H
þ
H
þ
H
þ
H
þ
½
þ
½
K
1
þ
½
K
1
K
2
þ
½
and the fraction existing in the doubly deprotonated H
2
A
2
form is