Civil Engineering Reference
In-Depth Information
Check of Shear Resistance
A
v
f
y
=
p
=
p
ð
428
10
:
5
Þ
275
V
pl
,
Rd
¼
¼
¼
713,518
:
3N
g
M0
1
:
0
¼
713
:
5kN
>
Q
Ed
¼
567 kN Then O
ð
:
K
:
Þ
4.5.2 Design of the Cross Girders
The cross girders carry concentrated loads from the stringers as shown in
Figure 4.133
.
Therefore, we can analyze an intermediate cross girder as
follows:
Dead Loads
Reaction from stringers due to dead loads
¼
4
:
8
4
:
5
¼
21
:
6kN
m
Assuming the cross girders are simply supported by the main plate
girders, we can calculate the maximum shear force and bending moment
Own weight of cross girder
¼
3
:
0kN
=
4.8 × 4.5 = 21.6 kN
21.6 kN
21.6 kN
21.6 kN
g
vk
= 3.0 kN/m
A
B
1.8
1.8
0.9
0.9
1.8
1.8
Y
A
= 56.7 kN
Y
B
= 56.7 kN
9.0 m
56.7 kN
51.3
29.7
24.3
+
2.7
S.F.D.
2.7
-
24.3
29.7
51.3
58.8 kN
B.M.D.
+
97.2 kN m
97.2
145.8
145.8
147
Figure 4.133 Straining actions from dead loads acting on an intermediate cross girder.
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