Civil Engineering Reference
In-Depth Information
M
x
I
x
y ¼
257,896,800
150
800
3
12
400
¼
16
:
12MPa
=
M
y
I
y
x ¼
146,160,000
800
150
3
12
75
¼
48
:
72MPa
=
f
max
¼
48
ð
:
52 + 16
:
12 + 48
:
72
Þ ¼
113
:
4MPa
<
340MPa Then O
ð
:
K
:
Þ
4.3.3.35 Design of Joint J
1
It is now possible to design the joints of the main trusses after designing all
members and knowing all details regarding the joints. Let us start by design-
used, the following design values are calculated:
F
v,Rd
¼
176 kN (single shear) and 353 kN (double shear)
F
s,Rd
¼
117 kN (single shear) and 234 kN (double shear)
F
s,ult
¼
103 kN (single shear) and 206 kN (double shear)
Number of Bolts for the Vertical Member V
1
F
Ed
F
s
,
ult
¼
5240
8
103
¼
50
:
N
V
ðÞ¼
:
9 bolts, taken as 54 bolts (27 bolts in each side
acting in single shear)
Number of Bolts for the Diagonal Member D
1
N
D
ðÞ¼
5
206
¼
32
:
6 bolts, taken as 40 bolts (20 bolts in each side
acting in double shear)
F
Ed
6711
:
F
s
,
ult
¼
4.3.3.36 Design of Joint J
2
Following the same procedures adopted for the design of joint J
1
, we can
sioned bolts as follows.
Number of Bolts for the Vertical Member V
2
N
V
ðÞ¼
F
Ed
4195
1
103
¼
40
:
F
s
,
ult
¼
:
7 bolts, taken as 48 bolts (24 bolts in each side
acting in single shear)
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