Civil Engineering Reference
In-Depth Information
Factored distributed wind loads
¼ q
WL
g
q
¼
9
:
03
1
:
7
¼
15
:
351 kN
=
m
R
A
¼
15
:
351
60
=
2
¼
460
:
53 kN
a¼
tan
1
6
ðÞ¼
45
=
6kN
The cross section of the bracing member (see
Figure 4.28
) can be
determined as follows:
l
b
x
¼
8490mm,
F
D
¼
460
:
53
=
ð
2
sin45
Þ ¼
325
:
l
b
y
¼
1
:
2
8490
¼
10,190mm
Choose two angles back-to-back 150
150
15, with 10 mm gusset plate
between them (
Figure 4.89
)
:
4cm
2
,
A¼
2
43
:
2
¼
86
:
i
x
¼
4
:
59 cm,
e ¼
4
:
26 cm,
q
4
2
59
2
+4
i
y
¼
:
ð
:
26 + 1
=
2
Þ
¼
6
:
61 cm
r
235
275
e ¼
¼
0
:
924
L
cr
i
1
l
1
l¼
l
1
¼
93
:
9
0
:
924
¼
86
:
7636
8490
45
1
l¼
7636
¼
2
:
13
:
9
86
:
The axial compressive force in the diagonal bracing member
(
N
Ed
¼
325.6 kN):
R
A
R
B
60 m
B
A
q
WL
= 15.35 kN/m
Figure 4.89 Loads on the lower wind bracing.
Search WWH ::
Custom Search