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and
F( s ) ¼ ( sI A ) 1
(
3
:
198
)
Therefore,
w( t ) ¼ L 1
[( sI A ) 1
]
(
3
:
199
)
Example 3.49
Find e At if
3
1
A ¼
0
4
S OLUTION
Using Laplace transform, we have
1
1
s þ
31
s þ
4
1
(sI A) 1
F
(s)
¼
¼
¼
0
s þ
4
s 2
0
s þ
3
þ
7s þ
12
or
2
4
3
5
s þ
4
1
(s þ
3)(s þ
4)
(s þ
3)(s þ
4)
F
(s)
¼
s þ
3
0
(s þ
3)(s þ
4)
Partial fraction of the entries of matrix
F
(s) yields
2
4
3
5
1
s þ
1
s þ
1
s þ
3 þ
3
4
F
(s)
¼
1
s þ
0
4
Hence,
e 3t
e 3t
þ e 4t
e At
¼ L 1 (sI A) 1
¼
e 4t
0
3.11.7 M ATRIX E XPONENTIAL F UNCTION A k
Matrix exponential A k has applications in design of discrete time-control systems. It
is the state-transition matrix of LTI discrete systems in state-space form. It can be
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