Environmental Engineering Reference
In-Depth Information
4
τ −τ −
4
A
2
l
Rp
τ
0
ef
0
ef
0
ef
τ =τ −
,
τ =
n
1
n
1
(4.17)
0
ef
0
ef
0
ef
n
n
1
3
0
D
4
τ−
4
ef
n
1
The first component in Eq. (4.12) represents the contribution to the fluid flow due
to the slippage, and it becomes clear that the slippage significantly enhances the
flow rate in the nanotube, when
h >»D .
This result is consistent with experimental and theoretical results of Kalra et
al. [34], Majumder et al. [41], Skoulidas et al. [66], Hummer et al. [28], and Holt
et al. [25], which show that water flow in nanochannels can be much higher than
under the same conditions, but for the liquid continuum.
In the absence of slippage
2
l
v
pR
0
the Eq. (4.16) has a trivial solution 0
e t= .
e
1
0
4.3
THE RESULTS OF THE CALCULATIONS
Let's determine the dependence of the effective critical inner shear stress 0ef = τ
on the radius of the nanotubes, by taking necessary values for calculations
e from the work of Thomas John and McGaughey Alan [73]. The results
of calculations at D p/l = 2.1×10 14 Pa/m are in the tablebelow:
Q /
Q
P
TABLE 4.2
Results of the Calculations
τ (Па)
0ef = 0
R , м
e
Q /
Q
P
0.83×10 -9
498,498
350
1.11×10 -9
577,500
200
1.385×10 -9
632,599
114
1.665×10 -9
699,300
84
1.94×10 -9
782,208
68
2.22×10 -9
855,477
57
2.495×10 -9
932,631
50
Calculations show that the value of effective internal shear stress depends on
the size of the nanotube. Figure 4.14 shows the dependence
on the nanotube
τ
0ef = 0
radius, and Fig. 4.15 shows the structure of the flow.
 
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