MICRO AND NANOSCALE SYSTEMS - Foundations of Nanotechnology: Pore Size in Carbon-Based Nano-Adsorbents - page 183

n

n

∑ =

M = m

∑ =

obvious that and g = 1 . The volume fraction is , where

i

i

i 1

i 1

v -partial volume ofcomponentmixtures.
Similarly, we have

Depending on specificity of tasks the gas constant of the mixture may be de-

termined as follows:

If we know the gas constant , the seeming molecular weight of the mixture

is equal to:

The pressure of the gas mixture p is equal to the sum of the partial pressures
of individual components in the mixture p i :

i  1 n

 

p p

(2.5)

i

i  1

Partial pressure p i -pressure that has gas, if it is one at the same temperature
fills the whole volume of the mixture .
With various methods of setting the gas mixture partial pressures

pg m

m

p = pr

p = pr ; p =

i cm

; (2.6)

i i

i 11

i

From the Eq. (2.6) we see that for the calculation of the partial pressures p i nec-
essary to know the pressure of the gas mixture, the volume or mass fraction i of
the gas component, as well as the molecular weight of the gas mixture m and the
molecular weight of i of gas mi. i .
The relationship between mass and volume fractions are written as follows:

m r v R m

g =

i

=

i i

=

см

r =

i

r

i i i

m r v R m

см см см i см