Biomedical Engineering Reference
In-Depth Information
and
M
M
M
M
j
log
ʻ
|
ʱ
|
M
log
|
ʱ
|
|
ʨ
|
log
|
ʻ
j
ʱ
|−
log
|
ʻ
j
ʨ
|=
|
ʨ
|
=
(5.95)
M
j
ʻ
j
=
1
j
=
1
j
=
1
hold. The proof of Eq. (
5.94
) is presented in Sect.
5.7.2
. Also, we can show
⊡
⊤
⊡
⊤
M
M
L
⊣
⊦
=
⊣
⊦
a
j
ʻ
j
ʱ
1
ʻ
j
ʱ
A
j
,
E
A
a
j
E
A
j
=
1
j
=
1
=
M
L
M
L
1
ʻ
j
[
ʨ
−
1
1
ʻ
j
ʱ
A
j
,
+
=
1
ʻ
j
ʱ
]
,
j
=
1
=
j
=
1
=
M
L
L
1
ʻ
j
ʱ
A
j
,
+
1
ʱ
[
ʨ
−
1
=
M
]
,
j
=
1
=
=
M
tr
ʱʨ
−
1
j
=
1
¯
M
a
j
ʻ
j
ʱ
¯
=
a
j
+
.
(5.96)
By substituting the above three equations into Eq. (
5.93
), we obtain the expression
for the free energy:
K
K
K
2
log
|
ʛ
|
1
2
1
2
y
k
ʛ
u
k
ʓ
¯
F
=
|
ʓ
|
−
y
k
+
1
¯
u
k
k
=
1
k
=
M
tr
ʱʨ
−
1
M
2
log
|
ʱ
|
1
2
M
2
a
j
ʻ
j
ʱ
¯
+
|
ʨ
|
−
1
¯
a
j
−
.
(5.97)
j
=
Note here that
tr
tr
ʛ
¯
A
j
=
1
¯
M
ʱ
¯
A
T
ʱ
¯
A
T
a
j
ʻ
j
ʱ
¯
¯
A
a
j
=
ʛ
=
.
(5.98)
Thus, we have
M
M
tr
ʱʨ
−
1
tr
¯
A
T
ʨ
−
1
ʛ
¯
A
a
j
ʻ
j
ʱ
¯
1
¯
a
j
+
=
ʱ
+
M
j
=
tr
ʱ
−
1
=
ʱ
M
=
ML
.
(5.99)