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blocks marked no obstacle (in the function nextblock ) minimizes the number of in-
side switches. Choosing the rightmost empty block, at each step also contributes to
minimizing the number of inside switches of a scan.
The SES algorithm has complexity O (N 2 M) . The functions rightmost and
nextblock are both bounded by the number of rows, hence they are both O (N ) .
The SES algorithm's outer loop iterates at most N times and its inner loop iterates at
most M times. Finally, the body of the inner loop takes O (N ) times due to the call
to nextblock . Consequently, the inner loop has complexity O (N M) and so does the
body of the outer loop.
Figure 41 depicts the snap shots of a running example of SES algorithm to re-
trieve fourteen objects from a five-parallel channel configuration. For this request,
MAX _ cut is 3, MAX _ total is 5 and at least 3 passes with at least 7 switches are re-
quired to retrieve the requested objects (numbers in the captions represent the line
number in SES algorithm).
SES Algorithm
1. if ( MAX _ total = MAX _ cut )
2.
use Row Scan;
3. else
4.
Rows ={ 1 ,...,N}
/* Rows we can compress */
5.
repeat until ( MAX _ total = MAX _ cut ){
6.
j = 1;
7.
i = nextblock ( Rows ,j)
8.
k = freeright (i, j )
/* free block is C ij to C ik */
9.
repeat until k = M {
i
= nextblock ( Rows ,k)
10.
k = freeright (i ,j)
11.
12.
C ia = C i a for 1 a<k
/* compress channels */
13.
C i k = no obstacle
/* indicate a switch occurs */
i = i
14.
15.
j = k
16.
}
17.
MAX _ total = MAX _ total 1
18.
Rows = Rows −{i}
/* delete the empty row */
19.
}
An Empty block without an obstacle ( Definition 14 ) represents a channel switch.
As one can conclude, in the first pass, objects 1, 3, 5, and 3 are retrieved. During
the second pass, objects 4, 7, 8, 9, and 10 are fetched. Finally, during the third pass,
objects 11, 13, 12, 14, and 6 are retrieved.
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