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The volumetric fl ow fl ux Q is thus calculated as
RZ
()
Q
=
2
π
rudr
0
(18)
{}
2
QRz
=
π
()
u
Therefore, Eqs. (17) and (18) reduces the form
n
+
1
n
+
1
2
π
R
⎧∂
p
B
⎧∂
p
B
Q
=−
m
r
2
τ
m
R
2
τ
(19)
1
H
1
H
p
B
z
z
z
z
n
2
m
m
2
1
z
z
Again, Eqs. (15) and (19) reduces the form
n
+
1
n
+
1
π
R
2
⎧∂
p
B
⎧∂
p
B
Q
=−
m
r
2
τ
m
R
2
τ
1
H
1
H
p
B
z
z
z
z
n
2
m
m
2
1
z
z
1
1
n
+
1
n
+
1
n
{(
k n
+
3)}
⎧ ∂
p
B
⎧ ∂
p
B
n
+
3
n
1
(20)
τ
=−
(1)
mr
2
τ
mR
2
τ
+
τ
n
R
1
H
1
H
H
p
B
z
z
z
z
n
+
2
1
2{
Rm
m
}
n
2
1
z
z
Shear stress is considered as
,
τ
u
r
τ
Thus,
= − k (
) r = R
(21)
where
k =
μ
u
r
τ
Therefore,
= −
μ
(
) r = R
(22)
Differentiating Eq. (17) with respect to r and substituting the value in
Eq. (22) we obtain shear stress,
 
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