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10.4.1 The Hoory Bound
Theorem 4.1 (Hoory [ Hoo02 ]) Let G
= (
V L ,
V R ,
E
)
be a bipartite graph of girth
g =
, minimum degree at least 2 and the left and
right average degrees d L and d R . Then,
2 r, with n L =|
V L |
and n R =|
V R |
r
1
2 (
2 ,
)
)
n L
0 (
d R
1
d L
1
i =
r
1
2 (
2 .
)
)
n R
0 (
d L
1
d R
1
i
=
For bipartite graphs the girth is always even. We then have the following variant
of Observation 3.2.
Observation 4.2
Let G
= (
V L ,
V R ,
E
)
be an undirected bipartite graph with
|
V L |=
n L and
|
V R |=
n R and girth g =
2 r. Let e be an edge of G and suppose
e 1 and
e 2 be
its directed versions in G, such that
e 1 E LR and
e 2 E RL . Then,
r
2 ∈−
r
2 ↆ−
1
1
n L
n 2 i + 1 (
e 1 ) +
n 2 i (
e 2 ).
i
=
0
i
=
0
We will prove the Theorem 4.1, assuming the following lemma, which is the main
technical part of Hoory [ Hoo02 ]. In Sect. 10.4.2 , we will present the proof of this
lemma using the language of entropy.
Lemma 4.3
be an undirected simple bipartite graph with n L
vertices on the left and n R vertices on the right, girth g , minimum degree at least two
and average left and right degrees, respectively d L and d R .
Let G
= (
V L ,
V R ,
E
)
E LR ,
(a) If
e
is
a
uniformly
chosen
random
edge
in
then
E[
n 2 i + 1 (
e
) ]≥
i
+
1
i
(
d R
1
)
(
d L
1
)
(
i
1
)
.
E RL ,
(b) If
e
is
a
uniformly
chosen
random
edge
in
then
E[
n 2 i (
e
) ]≥
i
i
(
d R
1
)
(
d L
1
)
(
i
1
)
.
Proof of Theorem 4.1 We will prove the bound for n L . The proof for n R case is
similar. Let
e 1 be chosen uniformly at random from E LR and let
e 2 be its companion
edge (going in the opposite direction). Note that
e 2 is also uniformly distributed in
E RL . Then, from Observation 4.3, Lemma 4.3 and linearity of expectation we obtain
r
2 ∈−
r
2 ↆ−
1
1
r
1
2 (
2 .
)
)
n L ≥ E
n 2 i + 1 (
e 1 ) +
n 2 i (
e 2 )
0 (
d R
1
d L
1
i
=
0
i
=
0
i
=
 
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