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If we have a set of polynomials with distinct leading monomials, then they are
clearly linearly independent. Hence, one way of lower bounding the dimension of
a space of polynomials is to find a sufficiently large set of polynomials with dis-
tinct monomials in the space. The vector space of polynomials we are interested is
˃ = k
, and if we choose a structured polynomial f we can hope to be able to
estimate the number of distinct leading monomials in this vector space.
(
f
)
5.9.3.1 Shifted Partials of the Determinant and Permanent
[ d ] [ d ] circuits was by Gupta, Kamath, Kayal,
and Saptharishi [ GKKS13 ] for the determinant and the permanent polynomials. We
shall describe the lower bound for Det n , although it would carry over immediately
to Perm n as well. As mentioned earlier, we wish to estimate the number of distinct
The first lower bound for
leading monomials in ˃ = k
span x ˃ = k Det n .[ GKKS13 ] made a
relaxation to merely count the number of distinct leading monomials among the
Det n )
(
=
generators x ˃ = k Det n instead of their span.
The first observation is that any k -th order partial derivative of Det n is just an
(
minor. Let us fix a monomial ordering induced by the lexicographic
ordering on the variables:
n
k
) × (
n
k
)
x 11
x 12 ··· ≡
x 1 n
x 21 ≡ ··· ≡
x nn .
Under this ordering, the leading monomial of any minor is just the product of vari-
ables on the main diagonal of the submatrix corresponding to the minor, and hence is
a term of the form x i 1 j 1 ...
x i ( n k ) , j ( n k ) where i 1 < ··· <
i n k and j 1 < ··· <
j n k ;
let us call such a sequence of indices as an
(
n
k
)
-increasing sequence in
[
n
]×[
n
]
.
Further, for any
-increasing sequence, there is a unique minor M whose
leading monomial is precisely the product of the variables indexed by the increas-
ing sequence. Therefore, the task of lower bounding distinct leading monomials in
(
n
k
)
x ˃ = k Det n reduces to the following combinatorial problem:
Claim 48
For any k
, >
0 , we have
# monomials of degree
( +
n
k
)
that
[ Kay ]
k ,
(
Det n )
.
contain an
(
n
k
)
-increasing sequence
We could start with an
(
n
k
)
-increasing sequence, and multiply by a monomial
of degree
to obtain a monomial containing an increasing sequence. Of course, the
issue is that this process is not invertible and hence we might overcount. To fix this
issue, [ GKKS13 ] assign a canonical increasing sequence to every monomial that
contains an increasing sequence and multiply by monomials of degree
that do not
change the canonical increasing sequence.
Definition 49 Let D 2 = x 1 , 1 ,...,
x n 1 , n , the main diagonal
and the diagonal just above it. For any monomial m define the canonical increasing
x n , n ,
x 1 , 2 ,
x 2 , 3 ,...,
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