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Fig. 1.1 Membership
functions of the fuzzy
system
μ i 1 (
x i ) + μ i 2 (
x i ) =
1
(1.17)
For this case which is widely used, it can be easily demonstrated (Jiménez et al.
2012 ) that the matrix X is not of full rank and therefore X T X is not invertible,
which makes the mentioned method of TS invalid. This result can be easily proven
as follows:
Supposing that it exists:
n
f
:
−→
(1.18)
y
=
f
(
x
)
(1.19)
in which each row of the matrix X is of the form:
X k = μ 1 (
x k
x k 1 (
x k )
x k μ 2 (
x k 2 (
x k )
b x k
b
x k
b x k
b
x k a
b
x k a
b
=
x k
(1.20)
a
a
a
a
verifying that:
=
a
b x k
b
x k
1
b
x k
x k
a
x k
a
x k
0
(1.21)
a
b
a
b
a
b
a
b
1
The rank of X in this case is 3 in other words, the columns of X are linearly depen-
dent which in turn makes impossible the use of the above mentioned identification
method proposed in Takagi and Sugeno ( 1985 ). Analyzing another example of two
variables:
2
f
:
−→
(1.22)
y
=
f
(
x 1 ,
x 2 )
(1.23)
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