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.K
m
C x
1
/
2
v
s
K
i
nx
n1
K
m
.K
i
C x
3
/
2
x
3
v
m
Œ
K
m
2.K
m
C
x
1
/
x
1
K
m
C x
1
3
v
m
x
1
v
m
.K
m
C x
1
/
4
K
m
.K
m
C x
1
/
2
v
m
K
m
.K
m
C x
1
/
2
x
1
C
v
m
(5.22)
By substituting the relations about the derivatives
x
1
,
x
2
, and
x
3
and after performing
intermediate operations one finally obtains
v
m
v
s
K
i
K
i
C x
3
v
m
K
m
2.K
m
C
x
1
/
.K
m
C x
1
/
4
x
1
K
m
C x
1
x
.3/
1
D
v
s
K
i
K
i
C x
3
K
m
.K
m
C x
1
/
2
v
m
K
m
.K
m
C x
1
/
2
C
v
m
v
s
K
i
nx
n1
.K
i
C x
3
/
2
K
1
K
d
C x
2
K
1
x
2
C K
2
x
3
x
1
K
m
C x
1
x
2
3
v
m
v
d
v
m
.K
m
C x
1
/
2
v
s
K
i
nx
n1
K
m
3
.K
i
C x
3
/
2
v
s
K
i
n.n
1/x
n
3
.K
i
C
x
3
/
K
i
nx
n
3
2.K
i
C
x
3
/
.K
i
C x
3
/
4
C
.K
1
x
2
K
2
x
3
/
.K
i
C x
3
/
2
K
2
ŒK
1
x
2
K
2
x
3
C
v
s
K
i
nx
n1
3
v
s
K
i
nx
n1
.K
i
C x
3
/
2
K
1
x
1
K
s
3
(5.23)
By defining the control input
u
D K
s
and the following two functions
n
v
m
K
m
2.K
m
C
x
1
/
.K
m
C
h
v
s
i
x
1
/
2
oh
v
s
i
K
i
K
i
C
K
i
K
i
C
x
1
K
m
C
K
m
.K
m
C
K
m
.K
m
C
f.x/D
x
3
v
m
C
v
m
x
1
/
2
v
m
x
3
x
1
/
4
x
1
n
v
s
K
i
nx
n
1
x
3
/
2
K
1
oh
x
2
K
1
x
2
C K
2
x
3
i
x
1
K
m
C
x
2
K
d
C
v
m
x
1
3
.K
i
C
v
d
n
v
m
.K
m
C
x
1
/
2
v
s
K
i
nx
n
1
K
m
C
3
.K
i
C
x
3
/
2
v
s
K
i
n.n
1/x
n
3
.K
i
C
x
3
/
K
i
nx
n
3
2.K
i
C
x
3
/
.K
i
C
.K
1
x
2
K
2
x
3
/
x
3
/
4
x
3
/
2
K
2
o
ŒK
1
x
2
K
2
x
3
C
v
s
K
i
nx
n
1
3
.K
i
C
(5.24)
v
s
K
i
nx
n
1
.K
i
C x
3
/
2
K
1
x
1
3
g.x/ D
(5.25)