Civil Engineering Reference
In-Depth Information
Equation (8-3) of ACI 440.1R-06 is
β
f
f
E
⋅ε
c
f
cu
ρ
:0.85
=
=
0.0126
1
fb2
E
⋅ε
+
f
fu
f
cu
fu
The selected reinforcement ratio is smaller than the ratio corresponding
to the balanced conditions, as shown:
ρ
ρ
fb2
=
1.779
f_des2
Because the reinforcement is to be placed on two levels, an even number
of FRP bars is selected:
N bar2 := 8
The total area of FRP reinforcement is
A f2 := N bar2 ·A f_bar = 6.283·in. 2
The corresponding FRP reinforcement ratio is (Equation 8-2 of ACI
440.1R-06)
A
A
f2
ρ
:
=
=
0.00822
f2
c2
FRP bar spacing: The clear bar spacing is
bN
⋅ φ−−
c in
w
bar2
f_bar
c
s
:
=
=⋅
inf20_
f20_clear
N1
bar2
The minimum required bar spacing is
S f_min2 := max(1·in, ϕ f_bar ) = 1·in.
“OK” if s
>
s
f20_ clear
f_min2
Check_BarSpacing2 :
=
“Too many bars” therwise
Check_BarSpacing = “Too many bars”
TwoManyBars := ✓ □Check Box
The flexural FRP reinforcement is placed in two layers:
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