Civil Engineering Reference
In-Depth Information
l
emb1
= 12 in
Bar = “#4”
Bent_Bar = “Not needed in this
e
xample”
r
b
l
ltail
l
lbhf
b
beam
= 14 in
6.6.2 Case 2—Midspan
Reinforcement required to resist bending moments:
The same procedure
discussed for Case 1 is followed.
The effective reinforcement depth is
=−−
φ
f_bar
d:t
c
=⋅
7 n
.
f2
slab
c
2
φ
-factor
φ
=
0.65
b_trial
The longitudinal reinforcement ratio required for bending is
M
1
bd
u2
ρ
:
=
⋅
f_req_bend2
β
⋅
1
f2
φ⋅
f
⋅
d
2
⋅
0.15d
b_trial
fu
f 2
f2
=
0.00209
(M
=
5kip ft)
⋅
⋅
u2
The minimum reinforcement requirement has to be verified. Equation
(8-8) of ACI 440.1R-06 is used. If the failure is not governed by FRP rup-
ture, this requirement is automatically achieved:
4.9fpsi
f
⋅
′ ⋅
bd ,
300psi
f
(
)
c
2
A:
=
min
⋅
bd
⋅
=
0.315 inf
⋅
f_min2
f2
f2
fu
fu
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