Civil Engineering Reference
In-Depth Information
r
b
can be calculated as:
r
b
= (
D-
2
c
c
+ 1 in.)/2 = 11.5 in.
Where
c
c
= concrete cover to the center of #8
r
b
/
d
b
= 30.7
f
fb
=
f
fu
= 60.0 ksi
f
fv
= 24.0 ksi
V
f
=
A
fv
f
fv
d
/
s
= 16.0 kip
And the nominal shear strength:
V
n
=
V
c
+
V
s
= 43.7 kip
ϕ
V
n
= 32.8 kip
5.9.7 Shear walls
The in-plane shear strength of walls can be calculated similarly to columns;
however, for most cases Equation (5.58) can be simplified to obtain a more
straightforward solution. For a shear wall, the in-plane horizontal dimen-
sion,
l
w
,
is normally long enough to justify the approximation of γ
= (
l
w
-
c
c
)/
l
w
≈ 1. Furthermore, if the total vertical reinforcement,
A
f
,
is uniformly dis-
tributed throughout
l
w
,
the parameters in Equation (5.58) can be evaluated
as ρ
f
1
= 0 and ρ
f
2
=
A
f
/(2
bl
w
) = ρ
f
/2, where
b
is the thickness of the wall.
Substituting these values into Equation (5.58),
k
can be calculated as
ρ
+ρ
n
ff
k
=
(5.64)
1
n
ff
The contribution of horizontal (shear reinforcement) can be evaluated,
assuming that
d
= 0.8
l
w
(5.65)
COMMENTARY
Mohamed et al. [33] tested GFRP RC shear walls to attain strength and drift
data. Four large-scale shear walls were constructed and failed under quasi-
static reversed cyclic lateral loading. The GFRP RC walls had different aspect
ratios covering the range of medium-rise walls. Experimental results show
that properly designed and detailed GFRP RC walls can attain their flex-
ural capacities with no strength degradation and that shear, sliding shear, and
anchorage failures can be effectively controlled. Figure 5.12 shows a GFRP RC
shear wall tested and failed under lateral cyclic loads.
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