Digital Signal Processing Reference
In-Depth Information
Tutorial 23
Q: Find the autocorrelation function of x
ð
t
Þ¼
Q
1
ð
t
0
:
5
Þ:
Note that x(t)isadeterministic signal.
Solution:FromTables:R(s) = $
-
?
x(k)x(s + k)dk.NotethatR(s) = x(s)*x(-s).
We follow the same steps that are necessary to find the convolution of two signals.
From Tables:
Q
T
ð
t
Þ¼
1
;
T
=
2
t
T
=
2
0
;
elsewhere
¼
1
;
x
ð
k
Þ¼
Y
1
ð
k
0
:
5
Þ¼
1
;
0
:
5
k
0
:
5
0
:
5
0
k
1
)
0
;
elsewhere
0
;
elsewhere
8
<
:
9
=
;
¼
1
;
s
k
1
s
|{z}
start
|
{z
}
end
x
ð
s
þ
k
Þ¼
1
;
0
s
þ
k
1
)
0
;
elsewhere
0
;
elsewhere
Note that since we have x(s + k) inside the integral, a positive k-shift s will give
negative shift to the function w.r.t the y-axis (contrary to the case of convolution).
Now we move the function x(s + k) from left to right while x(k) is fixed. We get
the following cases:
Π
1
(
λ
)
1
λ
−1
0
1
x
(
λ
) =
Π
1
(
λ
− 0.5)
1
λ
−1
0
1
x
(
τ
+
λ
) [
τ
> 0 ]
1
λ
−1
0
1
−
τ
1 −
τ
(Start)
(End)
R
(
τ
)
1
τ
−1
0
1
Case 1:
1
s\0
ð
i.e.
;
s [ 1
Þ)
R
ð
s
Þ¼
0 [no overlap].
0
1
s\1
ð
i.e.
;
0\s
1
Þ)
R
ð
s
Þ¼
R
1
s
Case 2:
0
dk
¼
1
s
:
Case 3:
0
s
1
ð
i.e.
;
1
s
0
Þ)
R
ð
s
Þ¼
R
1
s
dk
¼
1
þ
s.
Case 4:
s [ 1
ð
i.e.
;
s\
1
Þ)
R
ð
s
Þ¼
0 [no overlap].
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