Digital Signal Processing Reference
In-Depth Information
Tutorial 23
Q: Find the autocorrelation function of x ð t Þ¼ Q 1 ð t 0 : 5 Þ:
Note that x(t)isadeterministic signal.
Solution:FromTables:R(s) = $ - ? x(k)x(s + k)dk.NotethatR(s) = x(s)*x(-s).
We follow the same steps that are necessary to find the convolution of two signals.
From Tables: Q T ð t Þ¼ 1 ; T = 2 t T = 2
0 ;
elsewhere
¼ 1 ;
x ð k Þ¼ Y 1 ð k 0 : 5 Þ¼ 1 ; 0 : 5 k 0 : 5 0 : 5
0 k 1
)
0 ;
elsewhere
0 ;
elsewhere
8
<
:
9
=
;
¼
1 ; s
k 1 s
|{z}
start
| {z }
end
x ð s þ k Þ¼ 1 ;
0 s þ k 1
)
0 ;
elsewhere
0 ;
elsewhere
Note that since we have x(s + k) inside the integral, a positive k-shift s will give
negative shift to the function w.r.t the y-axis (contrary to the case of convolution).
Now we move the function x(s + k) from left to right while x(k) is fixed. We get
the following cases:
Π 1 ( λ )
1
λ
−1
0
1
x (
λ
) =
Π 1 (
λ
− 0.5)
1
λ
−1
0
1
x ( τ + λ ) [ τ > 0 ]
1
λ
−1
0
1
τ
1 −
τ
(Start)
(End)
R (
τ
)
1
τ
−1
0
1
Case 1:
1 s\0 ð i.e. ; s [ 1 Þ) R ð s Þ¼ 0 [no overlap].
0 1 s\1 ð i.e. ; 0\s 1 Þ) R ð s Þ¼ R 1 s
Case 2:
0 dk ¼ 1 s :
Case 3: 0 s 1 ð i.e. ; 1 s 0 Þ) R ð s Þ¼ R 1 s dk ¼ 1 þ s.
Case 4: s [ 1 ð i.e. ; s\ 1 Þ) R ð s Þ¼ 0 [no overlap].
 
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