Digital Signal Processing Reference
In-Depth Information
Similarly,
R ð s Þ¼ G ð s Þ Y ð s Þ
ð 3 Þ
Y ð s Þ¼ D ð s Þ E ð s Þ
ð 4 Þ
Using (2), (3), and (4) we get: Y(s)[1 - D(s)G(s)] = D(s)X(s)
H ð s Þ¼ Y ð s Þ
D ð s Þ
1 D ð s Þ G ð s Þ :
)
X ð s Þ ¼
Q2:
Find the transfer function of the following feedback system.
+
+
_
X ( s )
x ( t )
R ( s )
D ( s )
Y ( s )
y ( t )
+
G ( s )
Tutorial 20
Q:
The relationship between Ff x ð t Þg and Lf x ð t Þg is given by:
F f x ð t Þg¼ L f x ð t Þgj s ¼ jx
or : X ð x Þ¼ X ð s Þ s ¼ jx
where x = 2pf. This holds on the condition that:
Z
1
x ð t j j dt\ 1 i.e :; x ð t Þ is absolutely integrable :
1
Now decide whether X(x) can be found from X(s) for the functions:
1. d(t), 2. u(t), 3. t n
u(t), n is integer C0.
Solution:
1. R 1
1 x ð t j j dt ¼ R 1
1 d ð t Þ dt ¼ 1\infty. Hence, X(x) = X(s)| s=jx .
From Tables: D ð s Þ¼ L f d ð t Þg¼ 1. )
D ð x Þ¼ D ð s Þ s ¼ jx
¼ 1.
2. R 1 1 u ð t j j dt ¼ R 1
u ð t Þ dt ¼ R 1
0 1 : dt !1 .
Hence, we cannot use X(x) = X(s)| s=jx .
Note that the Laplace transform of u(t) is: U ð s Þ¼ s
0
(Tables), and the Fourier
transform of u(t) is: U ð f Þ¼ 2 d ð f Þþ 1
(Tables).
j2pf
 
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