Digital Signal Processing Reference
In-Depth Information
Similarly,
R
ð
s
Þ¼
G
ð
s
Þ
Y
ð
s
Þ
ð
3
Þ
Y
ð
s
Þ¼
D
ð
s
Þ
E
ð
s
Þ
ð
4
Þ
Using (2), (3), and (4) we get: Y(s)[1 - D(s)G(s)] = D(s)X(s)
H
ð
s
Þ¼
Y
ð
s
Þ
D
ð
s
Þ
1
D
ð
s
Þ
G
ð
s
Þ
:
)
X
ð
s
Þ
¼
Q2:
Find the transfer function of the following feedback system.
+
+
_
X
(
s
)
x
(
t
)
R
(
s
)
D
(
s
)
Y
(
s
)
y
(
t
)
+
G
(
s
)
Tutorial 20
Q:
The relationship between
Ff
x
ð
t
Þg
and
Lf
x
ð
t
Þg
is given by:
F
f
x
ð
t
Þg¼
L
f
x
ð
t
Þgj
s
¼
jx
or : X
ð
x
Þ¼
X
ð
s
Þ
s
¼
jx
where x = 2pf. This holds on the condition that:
Z
1
x
ð
t
j j
dt\
1
i.e
:;
x
ð
t
Þ
is absolutely integrable
:
1
Now decide whether X(x) can be found from X(s) for the functions:
1. d(t), 2. u(t), 3. t
n
u(t), n is integer C0.
Solution:
1.
R
1
1
x
ð
t
j j
dt
¼
R
1
1
d
ð
t
Þ
dt
¼
1\infty. Hence, X(x) = X(s)|
s=jx
.
From Tables: D
ð
s
Þ¼
L
f
d
ð
t
Þg¼
1. )
D
ð
x
Þ¼
D
ð
s
Þ
s
¼
jx
¼
1.
2.
R
1
1
u
ð
t
j j
dt
¼
R
1
u
ð
t
Þ
dt
¼
R
1
0
1
:
dt
!1
.
Hence, we cannot use X(x) = X(s)|
s=jx
.
Note that the Laplace transform of u(t) is: U
ð
s
Þ¼
s
0
(Tables), and the Fourier
transform of u(t) is: U
ð
f
Þ¼
2
d
ð
f
Þþ
1
(Tables).
j2pf
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