Digital Signal Processing Reference
In-Depth Information
(B) In this part, the frequency response reminds us of the modulation property. It
can be written as:
H ð f Þ¼ G ð f f c Þþ G ð f þ f c Þ:
Hence, using Tables or Tutorial 13 we get:
h ð t Þ¼ 2g ð t Þ cos ð 2pf c t Þ¼ 2f c sinc 2 ð f c t Þ cos ð 2pf c t Þ:
Tutorial 15
Q:
Show that:
(A) x ð t Þ y ð t Þ F X ð f Þ Y ð f Þ
(B) x ð t Þ y ð t Þ F X ð f Þ Y ð f Þ
Solution:
(A)
Ff x ð t Þ y ð t Þg¼ Z
1
x ð t Þ y ð t Þ e j2pft dt
1
¼ Z
1
F 1 f X ð f Þg y ð t Þ e j2pft dt
1
2
3
¼ Z
1
Z
1
4
5 y ð t Þ e j2pft dt
X ð k Þ e þ j2pkt dk
1
1
2
3
¼ Z
Z
1
1
4
y ð t Þ e j2p ð f k Þ t dt
5
X ð k Þ
dk
1
1
|{z}
Y ð f k Þ
¼ Z
1
X ð k Þ Y ð f k Þ dk ¼ X ð f Þ Y ð f Þ:
1
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