Digital Signal Processing Reference
In-Depth Information
(B) In this part, the frequency response reminds us of the modulation property. It
can be written as:
H
ð
f
Þ¼
G
ð
f
f
c
Þþ
G
ð
f
þ
f
c
Þ:
Hence, using Tables or Tutorial 13 we get:
h
ð
t
Þ¼
2g
ð
t
Þ
cos
ð
2pf
c
t
Þ¼
2f
c
sinc
2
ð
f
c
t
Þ
cos
ð
2pf
c
t
Þ:
Tutorial 15
Q:
Show that:
(A) x
ð
t
Þ
y
ð
t
Þ
F
X
ð
f
Þ
Y
ð
f
Þ
(B) x
ð
t
Þ
y
ð
t
Þ
F
X
ð
f
Þ
Y
ð
f
Þ
Solution:
(A)
Ff
x
ð
t
Þ
y
ð
t
Þg¼
Z
1
x
ð
t
Þ
y
ð
t
Þ
e
j2pft
dt
1
¼
Z
1
F
1
f
X
ð
f
Þg
y
ð
t
Þ
e
j2pft
dt
1
2
3
¼
Z
1
Z
1
4
5
y
ð
t
Þ
e
j2pft
dt
X
ð
k
Þ
e
þ
j2pkt
dk
1
1
2
3
¼
Z
Z
1
1
4
y
ð
t
Þ
e
j2p
ð
f
k
Þ
t
dt
5
X
ð
k
Þ
dk
1
1
|{z}
Y
ð
f
k
Þ
¼
Z
1
X
ð
k
Þ
Y
ð
f
k
Þ
dk
¼
X
ð
f
Þ
Y
ð
f
Þ:
1
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