Digital Signal Processing Reference
In-Depth Information
n
o ¼ e jj :
2
1 þð 2pt Þ 2
Using duality of FT and part (A) above we get: F
k :
f
From Tables (scaling property) we have: s ð kt Þ$ jj S
Applying this to the above result we get:
()
¼ 2pe 2p jj
2
1 þð t Þ 2
F
Tutorial 13
Q: Determine the impulse response of the ideal bandstop filter whose frequency
response is shown below.
H ( f )
1
f , Hz
f 2
f 1
f 1
f 2
0
Solution: It is better that we arrange H(f) in terms of well-known functions. In
this question it can be written as follows:
H ð f Þ¼ 1 G ð f Þ;
where G(f) is shown below.
To find an explicit formula for G(f), let f 0 ¼ f 1 þ f 2
2
; B ¼ f 2 f 1 :
G ð f Þ¼ Y
B
ð f f 0 Þþ Y
B
)
ð f þ f 0 Þ¼ X ð f f 0 Þþ X ð f þ f 0 Þ;
where X ð f Þ¼ Q B ð f Þ .
Now from Tables we have:
L Q L ð f Þ) L sinc ð Lt Þ F Q L ð f Þ [multiply both sides by L]
Hence, for this question we have: Bsinc ð Bt Þ
|{z}
x ð t Þ
1. sinc ð Lt Þ F
1
F Y B ð f Þ
:
|{z}
X ð f Þ
2. x ð t Þ cos ð 2pf 0 t Þ F 2 X ð f f 0 Þþ 2 X ð f þ f 0 Þ;
F X ð f f 0 Þþ X ð f þ f 0 Þ
|{z}
G ð f Þ
)
2x ð t Þ cos ð 2pf 0 t Þ
|{z}
g ð t Þ¼ 2B sinc ð Bt Þ cos ð 2pf 0 t Þ
) h ð t Þ¼ F 1
f
1 G ð f Þ
F 1 fg F 1 G ð f f ¼ d ð t Þ g ð t Þ
¼ d ð t Þ 2B sinc ð Bt Þ cos ð 2pf 0 t Þ:
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