Digital Signal Processing Reference
In-Depth Information
n
o
¼
e
jj
:
2
1
þð
2pt
Þ
2
Using duality of FT and part (A) above we get:
F
k
:
f
From Tables (scaling property) we have: s
ð
kt
Þ$
jj
S
Applying this to the above result we get:
()
¼
2pe
2p
jj
2
1
þð
t
Þ
2
F
Tutorial 13
Q: Determine the impulse response of the ideal bandstop filter whose frequency
response is shown below.
H
(
f
)
1
f
, Hz
−
f
2
−
f
1
f
1
f
2
0
Solution: It is better that we arrange H(f) in terms of well-known functions. In
this question it can be written as follows:
H
ð
f
Þ¼
1
G
ð
f
Þ;
where G(f) is shown below.
To find an explicit formula for G(f), let f
0
¼
f
1
þ
f
2
2
;
B
¼
f
2
f
1
:
G
ð
f
Þ¼
Y
B
ð
f
f
0
Þþ
Y
B
)
ð
f
þ
f
0
Þ¼
X
ð
f
f
0
Þþ
X
ð
f
þ
f
0
Þ;
where X
ð
f
Þ¼
Q
B
ð
f
Þ
.
Now from Tables we have:
L
Q
L
ð
f
Þ)
L
sinc
ð
Lt
Þ
F
Q
L
ð
f
Þ
[multiply both sides by L]
Hence, for this question we have: Bsinc
ð
Bt
Þ
|{z}
x
ð
t
Þ
1. sinc
ð
Lt
Þ
F
1
F
Y
B
ð
f
Þ
:
|{z}
X
ð
f
Þ
2. x
ð
t
Þ
cos
ð
2pf
0
t
Þ
F
2
X
ð
f
f
0
Þþ
2
X
ð
f
þ
f
0
Þ;
F
X
ð
f
f
0
Þþ
X
ð
f
þ
f
0
Þ
|{z}
G
ð
f
Þ
)
2x
ð
t
Þ
cos
ð
2pf
0
t
Þ
|{z}
g
ð
t
Þ¼
2B sinc
ð
Bt
Þ
cos
ð
2pf
0
t
Þ
) h
ð
t
Þ¼
F
1
f
1
G
ð
f
Þ
g¼
F
1
fg
F
1
G
ð
f
f ¼
d
ð
t
Þ
g
ð
t
Þ
¼
d
ð
t
Þ
2B sinc
ð
Bt
Þ
cos
ð
2pf
0
t
Þ:
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