Digital Signal Processing Reference
In-Depth Information
Fig. 2.12 An example of a
recursive digital system
(leaky integrator)
x ( n )
y ( n )
z −1
b
Example (2)) The difference equation that describes the recursive system in Fig.
( 2.12 ) is given by:
y ð n Þ¼ x ð n Þþ by ð n 1 Þ;
ð 2 : 14 Þ
where, b is a multiplicative constant (gain). Taking the ZT of both sides of ( 2.14 )
yields:
Y ð z Þ¼ X ð z Þþ bz 1 Y ð z Þ:
Re-arranging terms leads to
½ 1 bz 1 Y ð z Þ¼ X ð z Þ:
)H ð z Þ¼ Y ð z Þ
:
1 bz 1 ¼ z
1
X ð z Þ ¼
z b
From Tables (z-Transform Pairs), the IZT is h(n) = b n u(n).
The system frequency response is:
H ð x Þ¼ H ð z Þj z ¼ exp ð jxT s Þ
¼ e jxT s
e jxT s b ¼ e j2pfT s
e j2pfT s b ¼ e j2pf = fs
e j2pf = f s b
¼ e j2pm
e j2pm b ¼ e jX
e jX b
where m = f/f s and X ¼ 2pm are the normalized cyclic frequency and normalized
angular frequency, respectively. The magnitude and phase responses are:
H ð x Þj¼j H ð e jxT s Þj¼ j e jxT s j
1
cos ð xT s Þ b j sin ð xT s Þj
j e jxT s b j ¼
1
½ cos ð xT s Þ b 2 ½ sin ð xT s Þ 2
¼
q
\H ð x Þ
b sin ð x T s Þ
1 b cos ð x T s Þ
¼ \H ð e jxT s Þ¼ tan 1
As a special case, let b = 0.5 and f s = 1 Hz (i.e., T s = 1 s). At f = 0.1 Hz (i.e.,
x = 2p(0.1) = 0.6283rad/s), the magnitude response is j H ð e jxT s Þj¼ 1 : 506 and
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