Information Technology Reference
In-Depth Information
Table 11.9 Second
differentiation stage to a
constant
Differential (depth)
(exponent)
Sequence
0
579111315171921
1
22222222
This gives exponent
=
1 and coefficient
=
2 for the second term.
(2 / 1)
=
2
Step 7 . Generating the next set of numbers using 2x we have:
24681012141618
Step 8 . Subtracting 2x from these new first set of numbers.
This because the sequence is (2x
+
=
3)
2x
3
(5
2) (7
4) (9
6) (11
8) (13
10) (15
12) (17
14) (19
16) (21
18)
=
333333333
Step 9. This gives the final term 3 at depth 0 so we have:
x 2
2x 1
3x 0
F(x)
=
+
+
which may be rewritten in a more normal form as
x 2
F(x)
=
+
2x
+
3
And is the original generating function abstracted from the sequence.
11.4.4
PRIME
This function generates sequences using the prime number sequence as its source.
The sequence generated can take on the general form as fir INTER:
A i Prime fi i +
S i =
k i
The basic sequences are generated from the Prime number sequence:
2357111317192329 .........
A simple example is the square of the prime numbers:
4 9 25 49 121 168 287 361 529 841
So you could have twice prime squared plus a constant. Such a complex form as this
is unlikely in normal intelligence tests.
 
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