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φ ( 1 )
φ ( 0 )
(
t
)
into the sum of a lower-resolution version of itself, namely,
(
t
)
, and the difference
g
g
φ ( 1 )
) φ ( 0 )
(
t
(
t
)
. Let's examine this difference over an arbitrary unit interval
[
k
,
k
+
1
)
:
g
g
c 0 , k 2 c 1 , 2 k
1
2
k
t
<
k
+
φ ( 1 )
g
) φ ( 0 )
g
c 0 , k 2 c 1 , 2 k + 1
(
t
(
t
) =
(32)
1
k
+
2
t
<
k
+
1
Substituting for c 0 , k from ( 27 ), we obtain
1
1
1
2
2 c 1 , 2 k +
2 c 1 , 2 k + 1
k
t
<
k
+
φ ( 1 )
g
) φ ( 0 )
g
(
t
(
t
) =
(33)
1
1
1
2 c 1 , 2 k
2 c 1 , 2 k + 1
k
+
2
t
<
k
+
1
Defining
1
2 c 1 , 2 k +
1
2 c 1 , 2 k + 1
d 0 , k =−
over the arbitrary interval
[
k
,
k
+
1
)
,
φ ( 1 )
g
) φ ( 0 )
g
(
t
(
t
) =
d 0 , k ψ 0 , k (
t
)
(34)
where
1
1
2
<
+
k
t
k
ψ 0 , k (
t
) =
(35)
1
1 k
+
2
t
<
k
+
1
But this is simply the k th translate of theHaar wavelet. Thus, for this particular case the function
can be represented as the sum of a scaling function and a wavelet at the same resolution:
φ ( 1 )
g
(
t
) =
c 0 , k φ 0 , k (
t
) +
d 0 , k ψ 0 , k (
t
)
(36)
k
k
In fact, we can show that this decomposition is not limited to this particular example. A
function in V 1 can be decomposed into a function in V 0 —that is, a function that is a linear
combination of the scaling function at resolution 0 and a function that is a linear combination
of translates of a mother wavelet. Denoting the set of functions that can be obtained by a linear
combination of the translates of the mother wavelet as W 0 , we can write this symbolically as
V 1 =
V 0
W 0
(37)
In other words, any function in V 1 can be represented using functions in V 0 and W 0 .
Obviously, once a scaling function is selected, the choice of the wavelet function cannot be
arbitrary. The wavelet that generates the set W 0 and the scaling function that generates the sets
V 0 and V 1 are intrinsically related. In fact, from ( 37 ), W 0
V 1 , and therefore any function
in W 0 can be represented by a linear combination of
{ φ 1 , k }
. In particular, we can write the
mother wavelet
ψ(
t
)
as
ψ(
t
) =
w k φ 1 , k (
t
)
(38)
k
or
w k 2
ψ(
t
) =
φ(
2 t
k
)
(39)
k
 
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