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Dividing the numerator by the denominator we get the following:
az 1
a 2 z 2
+
+
···
1
a
z
z
z
a
a
a
a 2 z 1
a 2 z 1
Thus, the quotient is
az 1
a 2 z 2
a n z n
1
+
+
+··· =
n
=
0
We can easily see that the sequence for which F
(
z
)
is the Z-transform is
a n u
f n =
[
n
]
12.9.4 Z-Transform Properties
Analogous to the continuous linear systems, we can define the transfer function of a discrete
linear system as a function of z that relates the Z-transform of the input to the Z-transform of
the output. Let
f n } n =−∞
g n } n =−∞
{
be the input to a discrete linear time-invariant system, and
{
be the output. If F
(
z
)
is the Z-transform of the input sequence, and G
(
z
)
is the Z-transform
of the output sequence, then these are related to each other by
G
(
z
) =
H
(
z
)
F
(
z
)
(116)
and H
is the transfer function of the discrete linear time-invariant system.
If the input sequence
(
z
)
f n } n =−∞
{
had a Z-transform of one, then G
(
z
)
would be equal to
(
)
H
z
. It is an easy matter to find the requisite sequence:
1 n
0
0 otherwise
=
f n z n
F
(
z
) =
=
1
f n =
(117)
n
=−∞
This particular sequence is called the discrete delta function . The response of the system to
the discrete delta function is called the impulse response of the system. Obviously, the transfer
function H
(
z
)
is the Z-transform of the impulse response.
12.9.5 Discrete Convolution
In the continuous time case, the output of the linear time-invariant systemwas a convolution of
the input with the impulse response. Does the analogy hold in the discrete case? We can check
this out easily by explicitly writing out the Z-transforms in Equation ( 116 ). For simplicity
 
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