Databases Reference
In-Depth Information
T A B L E 6 . 5
Updated count array for
zero-order context.
Letter
Count
Cum _ Count
t
1
1
h
1
2
i
2
4
s
2
6
b
2
8
Esc
1
9
Total_Count
9
As the MSBs of l and u are the same, we shift the MSB out and shift 0 into the LSB of l and 1
into the LSB of u . The transmitted sequence is now 011. Having escaped out of the first-order
contexts, we examine Table 6.5 , the updated version of Table 6.2 , to see if we can encode t
using a zero-order context. Indeed we can, and using the Cum _ Count array, we can update l
and u :
0
9
l
=
0
+
(
63
0
+
1
) ×
=
0
=
000000
1
9
u
=
0
+
(
63
0
+
1
) ×
1
=
6
=
000110
The three most significant bits of both l and u are the same, so we shift them out. After the
update we get
Transmitted sequence:
011000
:
l
000000
u
:
110111
bt has not occurred previously,
so we move directly to the first-order context t . The letter h has occurred previously in this
context, so we update l and u and obtain
The next letter to be encoded is h . The second-order context
/
Transmitted sequence
:
0110000
l
:
000000
u
:
110101
The method of encoding should now be clear. At this point the various counts are as shown
in Tables 6.6 - 6.8 .
Now that we have an idea of how the ppm algorithm works, let's examine some of the
variations.
 
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