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Let elements
a
2
,
1
and
a
2
,
2
be IMs and let
n
1
m
1
b
1
,
1
q
1
q
2
a
2
,
1
=
m
2
b
2
,
1
,
a
2
,
2
=
p
1
c
1
,
1
c
1
,
2
.
Then,
A
|
(
a
2
,
1
,
a
2
,
2
)
=
B
|
(
a
2
,
2
)
=
B
,
because
a
2
,
1
is not an element of
B
, where
n
1
l
2
l
3
k
1
0
a
1
,
2
a
1
,
3
m
1
b
2
,
1
00
m
2
b
2
,
2
00
B
=
and
|
(
a
2
,
2
,
a
2
,
1
)
=
|
(
a
2
,
1
)
=
,
A
C
C
because
a
2
,
2
is not an element of
C
, where
l
1
q
1
q
2
l
3
k
1
a
1
,
1
00
a
1
,
3
p
1
0
c
1
,
1
c
1
,
2
0
C
=
,
where, obviously,
B
.
Let
A
and
a
k
f
,
l
g
be as above, let
b
m
d
,
n
e
be the element of the IM
a
k
f
,
l
g
, and let
=
C
b
m
d
,
n
e
=[
R
,
S
,
{
c
t
u
,v
w
}]
,
where
K
∩
R
=
L
∩
S
=
P
∩
R
=
Q
∩
S
=
K
∩
P
=
L
∩
Q
=∅
.
Then,
(
A
|
(
a
k
f
,
l
g
))
|
(
b
m
d
,
n
e
)
=[
(
K
−{
k
f
}
)
∪
(
P
−{
m
d
}
)
∪
R
,(
L
−{
l
g
}
)
∪
(
Q
−{
n
e
}∪
S
{
α
β
γ
,δ
ε
}]
,
where
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