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2
1
3
1
2
3
1
1
d
,
3 ,
8
e
,
4 ,
4
g
,
5 ,
5
h
,
5 ,
5
1
1
3
1
a
,
2 ,
3
4 ,
5
0
,
1
0
,
1
0
,
1
1
1
2
b
,
3 ,
3
3 ,
0
0
,
1
0
,
1
0
,
1
G ∗ ) =
N 5 ,
1
1
1
2
4 (
c
,
3 ,
2
0
,
1
5 ,
5
0
,
1
0
,
1
1
2
1
3
1
d
,
3 ,
8
0
,
1
0
,
1
4 ,
5
0
,
1
3
1
2
1
e
,
4 ,
4
0
,
1
0
,
1
3 ,
6
0
,
1
2
3
3
1
g
,
5 ,
5
0
,
1
0
,
1
0
,
1
5 ,
5
and the new graph has the form
On the other hand, if we can apply, e.g., operator N 4 ,
over G ∗ , we obtain
3
2
1
3
1
1
7
2
3
1
1
d
,
3 ,
8
e
,
4 ,
4
f
,
10 ,
8
g
,
5 ,
5
h
,
5 ,
5
1
1
3
1
1
1
a
,
2 ,
3
4 ,
5
2 ,
4
0
,
1
0
,
1
0
,
1
1
1
2
b
,
3 ,
3
3 ,
0
0
,
1
0
,
1
0
,
1
0
,
1
1
1
c
,
3 ,
2
0
,
1
0
,
1
0
,
1
0
,
1
0
,
1
N 4 ,
G ∗ ) =
3 (
1
2
1
3
1
d
,
3 ,
8
0
,
1
0
,
1
0
,
1
4 ,
5
0
,
1
3
1
2
1
e
,
4 ,
4
0
,
1
0
,
1
0
,
1
3 ,
6
0
,
1
1
7
1
1
f
,
10 ,
8
0
,
1
0
,
1
0
,
1
0
,
1
3 ,
4
2
3
3
1
g
,
5 ,
5
0
,
1
0
,
1
0
,
1
0
,
1
5 ,
5
 
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