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Choosing gains
ρ
3
(
t
),
ρ
4
(
t
),
ρ
5
(
t
) as given by (12.56), (12.57) and (12.58) yields
V
≤−
ρ
1
e
1
−
ρ
2
e
2
−
ρ
7
e
3
−
ρ
8
e
4
−
ρ
9
e
5
−
ρ
6
e
6
+
Π
(12.77)
where
ρ
i
∈
R
,
∀
i
=
{
7
,
8
,
9
}
are strictly positive constants, and
Π
(
t
)
∈
R
is
Π
(
t
)
(
e
1
−
ρ
4
e
4
)
Ψ
1
+(
e
2
−
ρ
5
e
5
)
Ψ
2
+(
y
2
y
3
e
3
+
y
2
u
1
e
4
+
y
2
u
2
e
5
) ˜
ω
1
−
(
y
1
y
3
e
3
+
y
1
u
1
e
4
+
y
1
u
2
e
5
) ˜
ω
2
.
(12.78)
Thus, (12.77) can be upper bounded as
V
≤−
λ
V
+
Π
.
(12.79)
0. Taking the time derivative of
V
(
e
) and utilizing
(12.64), (12.65), (12.69)-(12.71), (12.74) yields
Case 2:
y
3
(
t
)
>
y
3
and
φ
(
t
)
>
V
=
e
1
(
e
4
−
y
1
b
3
e
3
−
ρ
1
e
1
+
Ψ
1
)+
e
2
(
e
5
−
y
2
b
3
e
3
−
ρ
2
e
2
+
Ψ
2
)+
α
e
3
(12.80)
e
3
+
e
4
[
b
3
u
1
e
3
+
y
3
b
3
e
4
+(
y
2
ω
1
−
y
3
−
y
3
−
φ
y
1
ω
2
)
e
4
+
y
2
u
1
˜
ω
1
δ
−
y
1
u
1
˜
ω
2
+
u
1
J
4
e
4
+
q
(
u
1
)
e
4
−
ρ
4
(
e
4
+
Ψ
1
)
−
e
1
]
+
e
5
[
b
3
u
2
e
3
+
y
3
b
3
e
5
+(
y
2
ω
1
−
y
1
ω
2
)
e
5
+
y
2
u
2
˜
ω
1
−
y
1
u
2
˜
ω
2
+
u
2
J
5
e
5
+
q
(
u
2
)
e
5
−
ρ
5
(
e
5
+
Ψ
2
)
−
e
2
]
+
e
6
(
c
1
b
3
e
3
−
ρ
6
e
6
)
.
0and
y
3
−
y
3
δ
Since
0, the bracketed term in (12.80) is strictly
positive, and the expression for
V
(
t
) can be upper bounded as in (12.77).
Case 3:
y
3
(
t
)
φ
(
t
)
>
0,
e
3
(
t
)
<
<
0. Taking the time derivative of
V
(
e
) and utilizing
(12.64), (12.65), (12.69)-(12.71), (12.75) yields
<
y
3
and
φ
(
t
)
<
V
=
e
1
(
e
4
−
y
1
b
3
e
3
−
ρ
1
e
1
+
Ψ
1
)+
e
2
(
e
5
−
y
2
b
3
e
3
−
ρ
2
e
2
+
Ψ
2
)+
α
e
3
e
3
+
e
4
[
b
3
u
1
e
3
+
y
3
b
3
e
4
+(
y
2
ω
1
−
y
3
−
y
3
−
φ
y
1
ω
2
)
e
4
+
y
2
u
1
˜
ω
1
δ
−
y
1
u
1
˜
ω
2
+
u
1
J
4
e
4
+
q
(
u
1
)
e
4
−
ρ
4
(
e
4
+
Ψ
1
)
−
e
1
]
+
e
5
[
b
3
u
2
e
3
+
y
3
b
3
e
5
+(
y
2
ω
1
−
y
1
ω
2
)
e
5
+
y
2
u
2
˜
ω
1
−
y
1
u
2
˜
ω
2
+
u
2
J
5
e
5
+
q
(
u
2
)
e
5
−
ρ
5
(
e
5
+
Ψ
2
)
−
e
2
]
+
e
6
(
c
1
b
3
e
3
−
ρ
6
e
6
)
.
0and
y
3
−
y
3
δ
Since
φ
(
t
)
<
0,
e
3
(
t
)
>
<
0, the bracketed term in (12.80) is strictly
positive, and the expression for
·
V
(
t
) can be upper bounded as in (12.77).
The results in Section 12.4.2.1 indicate that
˜
ω
(
t
)
→
0as
t
→
∞
, and hence,
Ψ
1
(
t
)
,
Ψ
2
(
t
)
,
Π
(
t
)
→
0as
t
→
∞
. Thus, the expression (12.79) is a linear system
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