Chemistry Reference
In-Depth Information
CH
3
O
HC
CH
δ
9.0
-
singlet
area = 1
9.8
δ
2.1
-
2.6
δ
0.8
-
doublet
area = 6
1.5
heptet
area = 1
b.
(CH
3
)
2
CHOCH(CH
3
)
2
C( CH
3
)
2
O
CH
δ
3.8
δ
0.9
doublet
heptet
area = 1 (2)
area = 6 (12)
CH
3
CH
=
CCl
2
c.
CH
3
C
H
δ
5.2
-
5.7
quartet
area = 1
δ
1.6
-
1.9
doublet
area = 3
d.
1,4-dimethoxybenzene
