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GIFWBM
p
,
q
,
r
GIFWBM
p
,
q
,
r
α
=
(α
1
,α
2
,...,α
n
)
β
=
(β
1
,β
2
,
Let
and
...,β
n
)
(α)
(β)
α
β
, and let
S
and
S
be the scores of
and
, then Eq. (
1.169
) is equal to
S
(α)
≤
. Now we discuss the following cases:
Case 1
If
S
S
(β)
(α) <
S
(β)
, then by Xu and Yager (2006)'s ranking method, it can be
obtained that
GIFWBM
p
,
q
GIFWBM
p
,
q
(α
1
,α
2
,...,α
n
)<
(β
1
,β
2
,...,β
n
)
(1.170)
Case 2
If
S
(α)
=
S
(β)
, then
⎛
α
k
w
i
w
j
w
k
⎞
1
p
+
q
+
r
n
1
⎝
1
p
q
r
⎠
−
−
μ
α
i
μ
α
j
μ
i
,
j
,
k
=
1
⎛
⎝
r
⎞
⎠
⎛
⎝
1
r
w
i
w
j
w
k
⎞
1
p
+
q
+
n
1
⎠
p
q
−
−
−
−
(
−
v
α
i
)
(
−
v
α
j
)
(
−
v
α
k
)
1
1
1
1
i
,
j
,
k
=
1
⎛
β
k
w
i
w
j
w
k
⎞
1
1
p
+
q
+
r
n
⎝
1
p
q
⎠
r
=
−
−
μ
β
i
μ
β
j
μ
i
,
j
,
k
=
1
⎛
r
⎞
⎠
⎛
r
w
i
w
j
w
k
⎞
1
p
+
q
+
n
1
⎝
⎝
1
⎠
p
q
−
1
−
−
−
(
1
−
v
β
i
)
(
1
−
v
β
j
)
(
1
−
v
β
k
)
i
,
j
,
k
=
1
(1.171)
Since
μ
α
i
≤
μ
β
i
and
v
α
i
≥
v
β
i
, for all
i
,wehave
⎛
α
k
w
i
w
j
w
k
⎞
1
p
+
q
+
r
1
n
⎝
1
p
q
r
⎠
−
−
μ
α
i
μ
α
j
μ
i
,
j
,
k
=
1
⎛
k
w
i
w
j
w
k
⎞
1
p
+
q
+
r
n
1
p
β
i
μ
q
β
j
μ
⎝
1
r
β
⎠
=
−
−
μ
(1.172)
i
,
j
,
k
=
1
and
⎛
r
w
i
w
j
w
k
⎞
1
p
+
q
+
r
n
1
⎝
1
p
q
⎠
1
−
−
−
(
1
−
v
α
i
)
(
1
−
v
α
j
)
(
1
−
v
α
k
)
i
,
j
,
k
=
1
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