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In-Depth Information
⎛
⎝
⎞
⎠
(
0
.
64
,
0
.
16
,
0
.
20
)(
0
.
71
,
0
.
17
,
0
.
12
)(
0
.
82
,
0
.
10
,
0
.
08
)(
0
.
62
,
0
.
14
,
0
.
24
)
(
0
.
59
,
0
.
21
,
0
.
20
)(
0
.
58
,
0
.
15
,
0
.
27
)(
0
.
62
,
0
.
24
,
0
.
14
)(
0
.
60
,
0
.
20
,
0
.
20
)
R
(
2
)
=
(
0
.
63
,
0
.
19
,
0
.
18
)(
0
.
80
,
0
.
15
,
0
.
05
)(
0
.
60
,
0
.
24
,
0
.
16
)(
0
.
56
,
0
.
14
,
0
.
30
)
(
0
.
62
,
0
.
19
,
0
.
19
)(
0
.
62
,
0
.
17
,
0
.
21
)(
0
.
64
,
0
.
20
,
0
.
16
)(
0
.
78
,
0
.
10
,
0
.
12
)
⎛
⎝
⎞
⎠
(
0
.
64
,
0
.
19
,
0
.
17
)(
0
.
68
,
0
.
10
,
0
.
22
)(
0
.
78
,
0
.
20
,
0
.
02
)(
0
.
64
,
0
.
20
,
0
.
16
)
(
0
.
62
,
0
.
19
,
0
.
19
)(
0
.
65
,
0
.
17
,
0
.
18
)(
0
.
66
,
0
.
24
,
0
.
10
)(
0
.
58
,
0
.
18
,
0
.
24
)
R
(
3
)
=
(
0
.
62
,
0
.
19
,
0
.
19
)(
0
.
80
,
0
.
10
,
0
.
10
)(
0
.
66
,
0
.
20
,
0
.
14
)(
0
.
62
,
0
.
20
,
0
.
18
)
(
0
.
59
,
0
.
19
,
0
.
22
)(
0
.
63
,
0
.
25
,
0
.
12
)(
0
.
64
,
0
.
22
,
0
.
14
)(
0
.
74
,
0
.
12
,
0
.
14
)
Also we aggregate the information of the four layers and get the membership
degree
μ
(
k
)
(
, the non-membership degree
v
(
k
)
(
y
j
)
y
j
)
and the hesitancy degree
π
(
k
)
(
y
j
)
of the system
y
j
with respect to the expert
e
k
:
4
i
=
1
μ
(
1
)
μ
(
1
)
(
y
1
)
=
(
y
1
)
w
i
=
0
.
67
×
0
.
2
+
0
.
71
×
0
.
3
+
0
.
78
×
0
.
4
+
0
.
64
×
0
.
1
=
0
.
7230
i
4
v
(
1
)
(
v
(
1
)
i
y
1
)
=
(
y
1
)
w
i
=
0
.
19
×
0
.
2
+
0
.
17
×
0
.
3
+
0
.
14
×
0
.
4
+
0
.
14
×
0
.
1
=
0
.
1590
i
=
1
π
(
1
)
1
−
μ
(
1
)
1
v
(
1
)
1
(
y
1
)
=
1
(
y
1
)
−
(
y
1
)
=
1
−
0
.
7230
−
0
.
1590
=
0
.
1180
In a similar way, we can calculate the values of the rest systems, which are all
represented in the intuitionistic fuzzy matrices
F
(
k
)
(
k
=
1
,
2
,
3
)
(Zhang and Xu
2012):
⎛
⎞
⎛
⎞
(
0
.
7230
,
0
.
1590
,
0
.
1180
)
(
0
.
7310
,
0
.
1370
,
0
.
1320
)
⎝
⎠
,
⎝
⎠
(
0
.
6570
,
0
.
1870
,
0
.
1560
)
(
0
.
6000
,
0
.
2030
,
0
.
1970
)
F
(
1
)
=
F
(
2
)
=
(
0
.
6740
,
0
.
1850
,
0
.
1410
)
(
0
.
6620
,
0
.
1930
,
0
.
1450
)
(
0
.
6400
,
0
.
1850
,
0
.
1750
)
(
0
.
6440
,
0
.
1790
,
0
.
1770
)
⎛
⎝
⎞
⎠
(
0
.
7080
,
0
.
1680
,
0
.
1240
)
(
0
.
6410
,
0
.
2030
,
0
.
1560
)
F
(
3
)
=
(
0
.
6900
,
0
.
1680
,
0
.
1420
)
(
0
.
6370
,
0
.
2130
,
0
.
1500
)
and then calculate the total membership degree
μ(
y
j
)
, the total non-membership
degree
v
and the total hesitancy degree of the system
y
j
according to the weights
of the experts:
(
y
j
)
3
1
μ
(
k
)
(
μ(
y
1
)
=
y
1
)η
k
=
0
.
723
×
0
.
4
+
0
.
731
×
0
.
3
+
0
.
708
×
0
.
3
=
0
.
7209
k
=
3
v
(
k
)
(
v
(
y
1
)
=
y
1
)η
k
=
0
.
159
×
0
.
4
+
0
.
137
×
0
.
3
+
0
.
168
×
0
.
3
=
0
.
1551
k
=
1
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