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Fig. 2.1 Classification of the building materials A j ( j = 1 , 2 , 3 , 4 , 5 )
A 1 ={
x 1 , [
0
.
70
,
0
.
75
] , [
0
.
10
,
0
.
15
] ,
x 2 , [
0
.
00
,
0
.
10
] , [
0
.
80
,
0
.
90
] ,
x 3 , [
0
.
15
,
0
.
20
] , [
0
.
60
,
0
.
65
] ,
x 4 , [
0
.
50
,
0
.
55
] , [
0
.
30
,
0
.
35
] ,
x 5 , [
0
.
10
,
0
.
15
] , [
0
.
50
,
0
.
60
] ,
x 6 , [
0
.
70
,
0
.
75
] , [
0
.
10
,
0
.
15
]}
A 2 ={
x 1 , [
.
,
.
] , [
.
,
.
] ,
x 2 , [
.
,
.
] , [
.
,
.
] ,
0
40
0
45
0
30
0
35
0
60
0
65
0
20
0
30
x 3 , [
0
.
80
,
1
.
00
] , [
0
.
00
,
0
.
00
] ,
x 4 , [
0
.
70
,
0
.
90
] , [
0
.
00
,
0
.
10
] ,
x 5 , [
0
.
70
,
0
.
75
] , [
0
.
10
,
0
.
20
] ,
x 6 , [
0
.
90
,
1
.
00
] , [
0
.
00
,
0
.
00
]}
A 3 ={
x 1 , [
0
.
20
,
0
.
30
] , [
0
.
40
,
0
.
45
] ,
x 2 , [
0
.
80
,
0
.
90
] , [
0
.
00
,
0
.
10
] ,
x 3 , [
0
.
10
,
0
.
20
] , [
0
.
70
,
0
.
80
] ,
x 4 , [
0
.
15
,
0
.
20
] , [
0
.
70
,
0
.
75
] ,
x 5 , [
0
.
00
,
0
.
10
] , [
0
.
80
,
0
.
90
] ,
x 6 , [
0
.
60
,
0
.
70
] , [
0
.
20
,
0
.
30
]}
A 4 ={
x 1 , [
0
.
60
,
0
.
65
] , [
0
.
30
,
0
.
35
] ,
x 2 , [
0
.
45
,
0
.
50
] , [
0
.
30
,
0
.
40
] ,
x 3 , [
0
.
20
,
0
.
25
] , [
0
.
65
,
0
.
70
] ,
x 4 , [
0
.
20
,
0
.
30
] , [
0
.
50
,
0
.
60
] ,
x 5 , [
0
.
00
,
0
.
10
] , [
0
.
75
,
0
.
80
] ,
x 6 , [
0
.
50
,
0
.
60
] , [
0
.
20
,
0
.
25
]}
Here we can use Algorithm 2.4 to classify the enterprises A j (
j
=
1
,
2
,
3
,
4
)
:
A j (
Step 1 In the first stage, each of the IVIFSs
j
=
1
,
2
,
3
,
4
)
is considered as a
unique cluster:
{ A 1 } , { A 2 } , { A 3 } , { A 4 }
Step 2 Compare each IVIFS A i with all the other three IVIFSs by using the
weighted Hamming distance ( 2.111 ):
d wH ( A 1 , A 2 ) =
d wH ( A 2 , A 1 ) =
d wH ( A 1 , A 3 ) =
d wH ( A 3 , A 1 ) =
0
.
4600
,
0
.
4012
d wH ( A 1 , A 4 ) =
d wH ( A 4 , A 1 ) =
d wH ( A 2 , A 3 ) =
d wH ( A 3 , A 2 ) =
0
.
2525
,
0
.
4237
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