Information Technology Reference
In-Depth Information
Fig. 2.1
Classification of the building materials
A
j
(
j
=
1
,
2
,
3
,
4
,
5
)
A
1
={
x
1
,
[
0
.
70
,
0
.
75
]
,
[
0
.
10
,
0
.
15
]
,
x
2
,
[
0
.
00
,
0
.
10
]
,
[
0
.
80
,
0
.
90
]
,
x
3
,
[
0
.
15
,
0
.
20
]
,
[
0
.
60
,
0
.
65
]
,
x
4
,
[
0
.
50
,
0
.
55
]
,
[
0
.
30
,
0
.
35
]
,
x
5
,
[
0
.
10
,
0
.
15
]
,
[
0
.
50
,
0
.
60
]
,
x
6
,
[
0
.
70
,
0
.
75
]
,
[
0
.
10
,
0
.
15
]}
A
2
={
x
1
,
[
.
,
.
]
,
[
.
,
.
]
,
x
2
,
[
.
,
.
]
,
[
.
,
.
]
,
0
40
0
45
0
30
0
35
0
60
0
65
0
20
0
30
x
3
,
[
0
.
80
,
1
.
00
]
,
[
0
.
00
,
0
.
00
]
,
x
4
,
[
0
.
70
,
0
.
90
]
,
[
0
.
00
,
0
.
10
]
,
x
5
,
[
0
.
70
,
0
.
75
]
,
[
0
.
10
,
0
.
20
]
,
x
6
,
[
0
.
90
,
1
.
00
]
,
[
0
.
00
,
0
.
00
]}
A
3
={
x
1
,
[
0
.
20
,
0
.
30
]
,
[
0
.
40
,
0
.
45
]
,
x
2
,
[
0
.
80
,
0
.
90
]
,
[
0
.
00
,
0
.
10
]
,
x
3
,
[
0
.
10
,
0
.
20
]
,
[
0
.
70
,
0
.
80
]
,
x
4
,
[
0
.
15
,
0
.
20
]
,
[
0
.
70
,
0
.
75
]
,
x
5
,
[
0
.
00
,
0
.
10
]
,
[
0
.
80
,
0
.
90
]
,
x
6
,
[
0
.
60
,
0
.
70
]
,
[
0
.
20
,
0
.
30
]}
A
4
={
x
1
,
[
0
.
60
,
0
.
65
]
,
[
0
.
30
,
0
.
35
]
,
x
2
,
[
0
.
45
,
0
.
50
]
,
[
0
.
30
,
0
.
40
]
,
x
3
,
[
0
.
20
,
0
.
25
]
,
[
0
.
65
,
0
.
70
]
,
x
4
,
[
0
.
20
,
0
.
30
]
,
[
0
.
50
,
0
.
60
]
,
x
5
,
[
0
.
00
,
0
.
10
]
,
[
0
.
75
,
0
.
80
]
,
x
6
,
[
0
.
50
,
0
.
60
]
,
[
0
.
20
,
0
.
25
]}
Here we can use Algorithm 2.4 to classify the enterprises
A
j
(
j
=
1
,
2
,
3
,
4
)
:
A
j
(
Step 1
In the first stage, each of the IVIFSs
j
=
1
,
2
,
3
,
4
)
is considered as a
unique cluster:
{
A
1
}
,
{
A
2
}
,
{
A
3
}
,
{
A
4
}
Step 2
Compare each IVIFS
A
i
with all the other three IVIFSs by using the
weighted Hamming distance (
2.111
):
d
wH
(
A
1
,
A
2
)
=
d
wH
(
A
2
,
A
1
)
=
d
wH
(
A
1
,
A
3
)
=
d
wH
(
A
3
,
A
1
)
=
0
.
4600
,
0
.
4012
d
wH
(
A
1
,
A
4
)
=
d
wH
(
A
4
,
A
1
)
=
d
wH
(
A
2
,
A
3
)
=
d
wH
(
A
3
,
A
2
)
=
0
.
2525
,
0
.
4237
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