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μ α >
Case 2
v α
1
v
1
v
1
2
α
α
α ) >
α ) =
(
1
μ α ) + (
1
v
(
1
v
α ) + (
1
v
1
2
ϑ(α) >
Case 3
μ α <
v
α
1
v α
1
v α
1
2
v α ) <
v α ) =
(
1
μ α ) + (
1
(
1
v α ) + (
1
1
2
ϑ(α) <
μ α and non-
membership degree v α change in specific ranges, whichwe can see from the contours.
In the following, we shall demonstrate it:
Let
In fact, for each value derived by Eq. ( 1.15 ), its membership degree
α = α ,
v α α )
be an IFV, then
(1) If
ϑ(α)
0
.
5, then
(a) When
π α =
0,
μ α and v α get the maximums, i.e.,
π α =
0
μ α +
v α =
1
and
1
v
α
ϑ(α) =
=
1
v
α
v
α =
1
ϑ(α) μ α = ϑ(α)
1
+ π α
(b) When
μ α =
0, v
gets the minimum, i.e.,
α
1
v
1
v
1
v
1
2
ϑ(α)
α
α
α
ϑ(α) =
=
=
v
α =
1
+ π α
1
+
1
μ α
v
2
v
1
ϑ(α)
α
α
then the ranges of
μ α and v α are as follows, respectively:
1
2
ϑ(α)
0
μ α ϑ(α),
v α
1
ϑ(α)
1
ϑ(α)
(2)If0
.
5
<ϑ(α)
1, then
(a) When
π α
=
0
α
and v α
get the maximums, i.e.,
μ α
= ϑ(α)
and
v α =
;
(b) When v α =
1
ϑ(α)
0
α gets the minimum, i.e.,
1
v α
1
v α
1
2
ϑ(α)
1
ϑ(α) =
=
=
μ α =
1
+ π α
1
+
1
μ α
v α
2
μ α
ϑ(α)
 
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