Information Technology Reference
In-Depth Information
J , 1
κ α α ( α ) = ( λ α v α α + κ α (
λ α v α μ α ))
1
1
1
1
α
=
λ
v α α + (
μ α )
(
κ α )
1
1
1 1
t
1
1
t
v α κ α λ α
0 λ
(
1
κ α )
(1.324)
α
t
=
For n
=
2, we have
μ J , n
κα ,λα (α) = μ α + κ α (
1
λ α v α μ α )
1
2
α
+ κ α
λ
v
α μ α κ α (
1
λ α
v
α μ α )
= μ α + (
1
μ α )(κ α + κ α (
1
κ α ))
v
α κ α λ α (
1
+ λ α κ α )
2 1
t
1
2
2 1 t
α
= μ α + (
1
μ α )
(
1
κ α )
v α κ α λ α
0 λ
(
1
κ α )
t
=
(1.325)
2
α
v J , 2
κ α α (α) = λ
v
(1.326)
α
Suppose it is true for n
=
p , that is,
p 1
μ α ) 1
p
p
1
t
t
μ J , p
κ α α (α) = μ α + (
(
κ α )
v α κ α λ α
0 λ
κ α )
1
1
(
1
α
t
=
(1.327)
p
α
v J , p
κα ,λα (α) = λ
v
(1.328)
α
then, when n
=
p
+
1, we have
p
1
μ α ) 1
p
p
1
t
t
μ J , p + 1
κ α α (α) = μ α + (
1
(
1
κ α )
v α κ α λ α
0 λ
(
1
κ α )
α
t
=
μ α ) 1
p
1
p
+
1
+ κ α
λ
v α μ α (
1
(
1
κ α )
α
p 1
p
1
t
t
+
v α κ α λ α
0 λ
κ α )
(
1
α
t
=
Search WWH ::




Custom Search