Information Technology Reference
In-Depth Information
μ
k
1 β i
=
i = 1 β i ,
v k
i = 1 β i
k
i
=
i = 1 (
β i ) i = 1 (
1
+
1
1
μ β i )
=
μ β i ) ,
i = 1 (
) i = 1 (
1
+
1
β i ) +
1
1
γ i = 1 v
β i
(1.250)
i = 1 (
) i = 1 v
1
+
1
)(
1
v
β i )) +
1
β i
Then we prove that Eq. ( 1.249 ) holds for n
=
k
+
1, that is,
k
i = 1 β i
β k + 1
1 + 1
1 μ
1 + 1 β k + 1
1 μ β k + 1
k
i = 1 β i
k
i = 1 β i
1 + 1
1 + 1 β k + 1 + 1 )
1 μ
1 μ β k + 1 ,
=
k
i = 1 β i
k
i = 1 β i
γ v k
i = 1 β i v β k + 1
1
1
1
) 1
v β k + 1 +
+
1
)
v k
i = 1 β i
+
1
1
)
v k
i = 1 β i
v β k + 1
(1.251)
By the operational laws for IFVs, we have
1 + 1
1 + 1 β k + 1
k
1 β i
i
=
1 + 1 )
1 + 1 β k + 1
i = 1 (
β i ) i = 1 (
μ β i )
i = 1 ( 1 + 1 β i ) + 1 ) i = 1 ( 1 μ β i )
1
+
1
1
=
1
1 μ β k + 1
i = 1 (
β i ) i = 1 (
1
+
1
1
μ β i )
i = 1 (
) i = 1 (
1
+
1
β i ) +
1
1
μ β i )
β i ) 1
β k + 1 γ i = 1 (
μ β i ) 1
μ β k + 1
γ i = 1 (
1
+
1
+
1
1
=
i = 1 ( 1 + 1 β i ) + 1 ) i = 1 ( 1 μ β i )
γ k + 1
i =
1 ( 1 + 1 β i ) γ k + 1
1 ( 1 μ β i )
i = 1 ( 1 + 1 β i ) + 1 ) i = 1 ( 1 μ β i )
i =
(1.252)
=
 
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