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Theorem 1.38
(Xia and Xu 2011) The aggregated value by using the GHIFWA
operator is also an IFV, and
⎛
⎝
1
,
n
1
λ
l
r
γ
μ
1
,
n
−
μ
GHIFWA
(α
1
,α
2
,...,α
n
)
=
,
n
n
1
λ
1
λ
l
1
r
1
l
1
r
1
2
μ
n
+
(γ
−
1
)μ
+
(γ
−
1
)
μ
n
−
μ
,
,
,
,
⎞
⎠
v
l
1
,
n
+
(γ
−
1
)
v
1
,
n
v
l
1
,
n
−
v
l
1
,
n
1
λ
1
λ
2
−
v
l
1
,
n
+
(γ
v
l
1
,
n
v
l
1
,
n
−
v
l
1
,
n
1
λ
1
λ
2
−
1
)
+
(γ
−
1
)
(1.243)
where
n
)μ
α
i
w
i
l
1
−
μ
α
i
))
λ
+
(γ
2
μ
n
=
(
1
+
(γ
−
1
)(
1
−
1
(1.244)
,
i
=
1
n
(
−
μ
α
i
))
λ
−
μ
α
i
w
i
1
μ
=
+
(γ
−
)(
1
1
1
(1.245)
,
n
i
=
1
v
α
i
w
i
n
v
l
1
,
n
=
α
i
))
λ
+
(γ
2
(
1
+
(γ
−
1
)(
1
−
v
−
1
)
(1.246)
i
=
1
n
(
v
α
i
w
i
v
1
,
n
=
v
α
i
))
λ
−
1
+
(γ
−
1
)(
1
−
(1.247)
i
=
1
w
i
α
i
Proof
Let
β
i
=
, then Eq. (
1.242
) can be written as:
n
⊕
w
i
α
i
n
⊕
1
β
i
1
λ
1
λ
GHIFWA
(α
1
,α
2
,...,α
n
)
=
=
(1.248)
i
=
1
i
=
and we first prove the following equation by using mathematical induction on
n
:
i
=
1
(
)μ
β
i
)
−
i
=
1
(
1
+
(γ
−
1
1
−
μ
β
i
)
n
⊕
1
β
i
=
i
=
1
(
)
i
=
1
(
−
μ
β
i
)
,
1
+
(γ
−
1
)μ
β
i
)
+
(γ
−
1
1
i
=
γ
i
=
1
v
β
i
i
=
1
(
)
i
=
1
v
(1.249)
1
+
(γ
−
1
)(
1
−
v
β
i
))
+
(γ
−
1
β
i
For
n
=
2, Eq. (
1.249
) holds obviously. Suppose that Eq. (
1.249
) holds for
n
=
k
,
that is,
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