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We estimate
E
[
μ
n
]
using ideas from [
11
]. Let
F
be the distribution function of
X
v
,
v
∈
V
. For any real number
t
,wehavethat
+
v
(
X
v
−
t
)
+
,
μ
n
≤
t
n
t
which gives that
E
[
μ
n
]
≤
h
(
t
)
:
=
t
+
[
1
−
F
(
x
)]
dx
,forany
t
∈
R
. Differentiating
n
t
n
1
n
)
F
−
1
h
(
·
)
one finds that its minimum is at
t
n
:
=
(
1
−
and so
E
[
μ
n
]
≤
t
n
+
[
1
−
e
−
λ
x
it follows that
E
1
F
(
x
)]
dx
.Since1
−
F
(
x
)=
[
μ
n
]
≤
λ
(
1
+
log
n
)
. Hence
2
λ
(
E
[
τ
]
≤
2
·
E
[
μ
n
]
≤
1
+
log
n
)
.
We summarize the preceding results into a Theorem which is an improvement of
the Main Theorem from [
2
].
Theorem 3.
Let G be a graph on n vertices and maximum degree
Δ
. If the number
of available colors is at least
2
and if all players adopt the simple strategy, then
for any starting assignment of colors, the network coloring game reaches a proper
coloring at time
Δ
+
τ
that is stochastically smaller than a random variable T , such that
2
,where
2
[
]
≤
λ
(
+
)
λ
≈
,
E
T
1
log
n
1
023
.
4.5 Proof of Theorem 2
This section is devoted to the proof of Theorem
2
. We want to show that the median
of
X
d
is
3
d
+
2
4
,where
X
d
is the number of different colors after a toss of
d
coins
that are colored using
d
colors. Before proving this theorem we need some notation
and remarks.
Suppose that we have
d
coins that are colored with
d
colors. Let
G
be the depen-
dency graph corresponding to this set of coins. We are going to orient
G
as follows.
Toss all the coins and orient each edge towards the vertex (color) that came up in
the toss. Thus a toss of the coins gives rise to an orientation on the edges of
G
.Asa
consequence,
X
d
=
≤
j
corresponds to the fact that
j
vertices have positive in-degree,
which means that
d
j
vertices must have in-degree 0. Also note that none of the
vertices of zero in-degree can be adjacent.
We denote the in-degree of a vertex
v
by deg
−
(
−
v
)
and by
Z
d
the number of ver-
tices of zero in-degree. Thus
X
d
=
Z
d
.
It turns out that the median of
X
d
can be estimated through the median of
E
d
,
the number of even in-degree vertices, whose distribution is easier to determine. We
will need the following two graph-theoretic results.
d
−
Lemma 6.
Suppose that G is a (possibly disconnected) graph on d vertices and m
edges. Fix some orientation on the edges and let O
d
,
m
,
E
d
,
m
be the number of odd
and even in-degree vertices respectively. Then the parity of E
d
,
m
equals the parity of
m
−
d.
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