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s : s i are integers, s i
i = 1 s i = s
n
B
=
0
,
Then A
B, and the following equality
min
s
f
(
s
)=
min
s
f
(
s
)
(3.41)
B
A
is satisfied. That is to say, the minimum of ( 3.32 ) subject to ( 3.33 ) is obtained with
an s
A.
Proof. The relation A
B is clear. To proof equality ( 3.41 ) first let us suppose d
>
0
.
n
i =
Let s
B be given, then
s i =
s and s i =
a i + δ i is satisfied, where
δ i ,
i
=
1
,
2
,...,
n ,
1
are integers. If every
δ i different from zero has the same sign (that is
δ i
0for
=
,
,...,
i
1
2
n )then
n
i = 1 s i =
n
i = 1 a i +
n
i = 1 δ i = s d +
n
i = 1 δ i
n
i = 1 δ i = d
and so s
A . If, on the contrary, not all the
δ i have the same sign, let us call
H 1 = {
i :
δ i >
0
},
H 2 = {
i :
δ i <
0
}.
We can write
n
i = 1 s i =
n
i = 1 a i +
H 1 δ i +
+
i
H 1 δ i +
H 2 δ i =
s
d
H 2 δ i =
s
.
i
i
i
δ i for i
Then
i H 1 δ i =
d
i H 2 δ i >
d , and we can select K
H 1 and
K such that
n
i =
δ i are integers, 1
δ i δ i and
1 δ i =
d . Now we can build s
A as follows
s i =
a i + δ i
for i
K
H 1 ,
s i =
a i
for i
K
.
We h ave
n
i = 1 c i ( s i r i )
2
= i K c i ( s i r i )
2
+ i K c i ( s i r i )
2
f
(
s
r
)=
i K c i ( s i r i )
2
+ i K c i ( a i r i )
2
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