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1 / b
i = 0
1 / b
i = 0 λ i β i = k
1 / b
i = 0 β i = m
i
β i =
and
so
1 / b
i = 0 β i /
1 / b
i = 0
v
(
a
,
b
)=
1
(
i
β i ) .
1
/
b
Thus, putting g j =( β j /
i
β i ) ,
a lower bound for v
(
a
,
b
)
is 1
H where
i = 0
max 1 / b
j = 0
H
=
g j
subject to
1 / b
j = 0 λ j g j =
1 / b
j = 0
jg j =
1
,
and
g j
0
(
j
=
0
,
1
,...,
1
/
b
) .
This is a linear program with dual
min x
+
y
subject to
λ i x
+
iy
1
,
x
,
y unrestricted
(
i
=
0
,
1
,...,
1
/
b
) .
Λ + and q
Λ be such that G
Let s
(
s
,
q
)=
G
,
where G
(
i
,
j
)
and G are given
,∈ Λ
by ( 9.4 )and( 9.5 ) respectively. It is routine to check that, for i
)= (
s
λ s )(
i
( λ q λ s )+ λ i (
s
q
) (
s
λ q
q
λ s ))
0
G
(
s
,
q
)
G
(
s
,
i
(
)(
)
s
λ
q
λ
s
λ
i
λ
q
s
i
s
Λ + ,
and that, for i
)= ( λ q
q
)(
i
( λ q λ s )+ λ i (
s
q
) (
s
λ q
q
λ s ))
0
G
(
s
,
q
)
G
(
i
,
q
.
(
s
λ
q
λ
)(
s
λ
i
λ
)
q
s
i
s
It is now straightforward to verify by the duality theorem that H
=
G
(
s
,
q
)
by
taking g q =
G
(
s
,
q
)
g s =(
s
λ s ) / (
s
λ q
q
λ s ) ,
g i =
0 otherwise and x
=
G
(
s
,
q
)
y
=(
s
q
) / (
s
λ q
q
λ s ) .
9.5 A Second Illustrative Example
In the previous section we showed that an optimal Defender strategy gives rise
to a number of chains of intervals and used this fact to obtain a lower bound for
v
(
a
,
b
) .
However the type of chains and the number of each type that give this lower
 
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