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Figure 3.1 Steady turbulent channel flow and its profiles of mean velocity U and
mean kinematic shear stress T 13 .
as well. We can then write U i
, and in steady conditions the
ensemble-averaged momentum equation (3.6) reduces to
=[
U(z), 0 , 0
]
2 U i
∂x j ∂x j .
∂x j u i u j =−
1
ρ
∂P
∂x i +
ν
(3.9)
This expresses a balance among the turbulent stress divergence, the mean pres-
sure gradient, and the viscous stress divergence. The homogeneity in y makes that
component equation vanish, so we have
uw
∂z
ν ∂U
∂z
1
ρ
∂P
∂x .
i
=
1:
=−
(3.10)
∂w 2
∂z =−
1
ρ
∂P
∂z .
i
=
3:
(3.11)
By differentiating Eq. (3.11) with respect to x , using homogeneity, and changing
the order of differentiation we conclude that
∂w 2
∂z =
∂x
1
ρ
∂x
∂P
∂z =−
1
ρ
∂z
∂P
∂x ,
0
=−
(3.12)
which implies that ∂P /∂x does not depen d on z . Equation (3.10) then implies that
the mean kinematic shear stress T 13 =−
+
ν∂U/∂z varies linearly with z ,as
sketched in Figure 3.1 . As we showed through Eq. (3.8) , the viscous part of the
shear stress is negligible except very near the walls.
uw
 
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