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where H ρ is the density scale height of the atmosphere, about 12 km. For boundary-
layer depths small compared to H ρ the second term on the right side of Eq. (9.24) is
not important. To evaluate the first term on the right we turn to the vertical equation
of mean motion:
∂U 3
∂t +
U j ∂U 3
∂u 3 u j
∂x j
1
ρ 0
∂P
∂x 3
g
θ 0 θ .
∂x j +
=−
2 3 jk j U k +
(9.25)
Let us first scale the terms in Eq. (9.25) . Let horizontal mean velocities scale with
U 0 , vertical mean velocity with W 0 , turbulent velocities with u , horizontal gradients
with L x , local time changes with L x /U , and vertical gradients with H . The mean
continuity equation implies
U 0
W 0
H
L x
,
(9.26)
so we have W 0 HU 0 /L x . Then the order of the terms in Eq. (9.25) is
time change , mean advection: U 0 H
L x
,
turbulent flux divergence: u 2
H ,
rotation: fU 0 ,
g
θ 0 θ .
buoyancy:
(9.27)
θ
10 2 ms 2 .If U 0
If
1 K, then the buoyancy term is of order 3
×
10ms 1 and H
10 3 m, the rotation and turbulence terms are of order 10 3 ms 2 ,
considerably smaller than the buoyancy term.
The size of the time-change and advection terms depends additionally on the char-
acteristic horizontal length scale L x .If L x is of the order of 10 4 m - which implies
a horizontal divergence of 10 m s 1 per 10 km, a fairly large value - then these
inertial terms are of order 10 3 ms 2 , again much smaller than the buoyancy term.
We conclude that if L x is sufficiently large we can use the hydrostatic
approximation to the U 3 -equation, writing it as
1
ρ 0
∂P
∂z =
g
θ 0 θ .
(9.28)
Differentiating (9.28) with respect to y and using the result in (9.24) provides an
expression for the z -variation of U g :
∂ θ
∂y +
f ∂U g
g
θ 0
fU g
H ρ =−
g
T 0
∂T
∂y +
fU g
H ρ
∂z =−
.
(9.29)
 
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