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we have formally introduced the vector function F G : W ! V :
p G ¼ F G p ð :
ð 4
:
8 Þ
In the same way, from ( 4.7 ), we derive the inverse F G : V F V ! W :
p G ¼ F G p ð :
ð 4
:
9 Þ
Example 4.2 To make the discussion less abstract, we give a very simple example.
Consider the case where we have only two products, i.e., n ¼ 2. Then we have
two single r ecommen da tions a 1 and a 2 and three multiple recommendations
a 1 ¼ að , a 2 ¼ að , a 3 ¼ a 1 ;
ð
a 2
Þ . This yields the following probability spaces:
n
n
o 0 p a i
o ,
p a 1
p a 2
p a 3
p a 3
ss 2
ss 0 1, p a 3
ss 1 þ p a 3
V
: ¼
ss 1 ;
ss 2 ;
ss 1 ;
ss 2 1
0 p a s 0
:
p a s 1
p a s 2
W
: ¼
;
ss 0 1
ss 1
ss 2
Let us consider the first “multiple” recommendation a 1 ¼ að . Then the relation
p a 1
p a 1
¼ F a 1
simply translates into
¼ F a 1
¼
:
p a 1
ss 1
p a 1
ss 1
p a 1
ss 1
For the global function F a G , we get
¼
¼ F a G
:
p a 1
ss 1
p a 2
ss 2
p a 1
ss 1
p a 1
ss 1
Same holds for the second “multiple” recommendation a 2 ¼ að . For t he thi rd
(a nd only real) multiple recommendation a 3 ¼ a 1 ;
Þ , the mapping p a 3
¼ F a 3
ð
a 2
p a 1 now becomes more complex:
0
1
p a 1
ss 1
p a 1
ss 1
1 p a 2
ss 2
þ p a 1
ss 1 p a 2
!
¼ F a 3
¼
@
A
ss 2
p a 1
ss 1 þ p a 2
p a 3
ss 1
p a 3
ss 2
p a 1
ss 1
p a 2
ss 2
ss 2
:
p a 2
ss 2
p a 2
ss 2
1 p a 1
ss 1
þ p a 1
ss 1 p a 2
p a 1
ss 1 þ p a 2
ss 2
ss 2
In this case, F a 3 is also our global function, i.e., F a G ¼ F a 3 . Thus, we arrive at
the complete global mapping:
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